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3 years ago

NEED ANSWER FAST WILL GIVE BRAINLIEST what is −3.9 − 8.9

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

6 0

Answer:
-12.8
Hope this helps! :)

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Find the area A of the sector of a circle of radius 90 in formed by central angle 1/6 radian.

miv72 [106K]

Answer:

2121 $in^{2}$ Rounded to the nearest inch.

Step-by-step explanation:

A = $\pi r^{2}$ Is the formula for a circle, but we only have a portion of a circle so we will have to adjust the formula for a part of the circle.

A = $\frac{\frac{\pi }{6} }{2\pi }$ $\pi r^{2}$ The $\frac{\pi }{6}$ is the part of the circle and the whole circle is 2 $\pi$

$\frac{\frac{\pi }{6} }{2\pi }$ is the same as $\frac{\pi }{6}$ ÷ $\frac{2\pi }{1}$ Which is the same as $\frac{\pi }{6}$ x $\frac{1}{2\pi }$ Which is the same a $\frac{1}{12}$

A = $\frac{1}{12}$ $\pi$ $90^{2}$

A = $\frac{1}{12}$ (3.14)(90)(90) = 2119.5. When you use the $\pi$ on your calculator you get a slightly different number. This is due to rounding.

A = 2120.575041

5 0

1 year ago

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle

zimovet [89]

Answer: $\left | 2t-5\right |,\ 2,\ 2t-5$

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

$s(t)=t^2-5t+1$

Speed of the particle is given by

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |$

Acceleration of the particle is

$\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2$

velocity can be negative, but speed cannot

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5$

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3 years ago

Using the graph determine the equation of the axis of symmetry

zalisa [80]

It’s is 1
wherever the vertex is, is the line of symmetry

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2 years ago

Help plz asap..... .

LenKa [72]

Answer:

Y=1

Step-by-step explanation:

cause 2x0/2 + 4 x 0 + 1 = 1

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Leni [432]

The answer for this question is B

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3 years ago

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