3 years ago

Dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget

Mathematics

1 answer:

Deffense [45]3 years ago

5 0

100 is the answerrrrrrrrrrrrrrrrrrr

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Find the value of an exterior angle of a polygon with 12 sides

Juli2301 [7.4K]

Answer:

$\huge \boxed{30\°}$

Step-by-step explanation:

To find the value of an exterior angle of a regular polygon, we can apply a formula.

$\displaystyle \frac{360}{n}$

$n = \sf number \ of \ sides$

$\displaystyle \frac{360}{12}=30$

3 0

3 years ago

Read 2 more answers

I need help with these as well

Mkey [24]

The answer to c. Is 8t+12g

4 0

3 years ago

A baby is weighed on a defective scale. He weighed 13 pounds. The baby weighs exactly 10 pounds. What is the percent error?

Eva8 [605]

Answer:

30%

Step-by-step explanation:

The answer is off by 30%, as the scale is off by 3 pounds. 3/10=30

4 0

3 years ago

4x+9y=69<br> X=69-8y<br> What is the solution of the system?

fomenos

(-3,9) The x axis is -3 and the y axis is 9

4 0

4 years ago

Find the lengths of the sides of the triangle PQR. P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) a. |PQ| = b. |QR| = c. |RP| =

Nat2105 [25]

Given :

Three points , P(4, 3, 4), Q(2, 1, 3), R(2, 7, 0) .

To Find :

The length of sides .

Given :

We know , length of two points P(x,y ,z) and Q(a,b,c) is given by :

$L=\sqrt{(x-a)^2+(y-b)^2+(z-c)^2}$

Length of PQ :

$PQ=\sqrt{(4-2)^2+(3-1)^2+(4-3)^2}\\\\PQ=\sqrt{4+4+1}=\sqrt{9}\\\\PQ=3$

Length of QR :

$QR=\sqrt{(2-2)^2+(1-7)^2+(3-0)^2}\\\\QR=\sqrt{0+6^2+3^2}\\\\QR=\sqrt{36+9}\\\\QR=\sqrt{45}\\\\QR=3\sqrt{5}$ :

Length of RP :

$RP=\sqrt{(2-4)^2+(7-3)^2+(0-4)^2}\\\\RP=\sqrt{2^2+4^2+4^2}\\\\RP=\sqrt{4+16+16}\\\\RP=\sqrt{36}\\\\RP=6$

Hence , this is the required solution .

4 0

3 years ago