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slavikrds [6]
4 years ago
5

- Passing through (-2, -11) and PERPENDICULAR to a + 4y - 8

Mathematics
1 answer:
abruzzese [7]4 years ago
6 0

(3,-2) is your answer can i have brainlest please

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What is the common denominator 2/5 and 2/3
Keith_Richards [23]
The common denominator would be 15 since 5 times 3=15. 
8 0
3 years ago
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Write a variable expression for this amount a number x decreased by 6
ANEK [815]
I'm not exactly sure what you're asking but <em />I'll give it a go. 
A = x -6
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3 years ago
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Margo missed 24.6% of the free throw shots in a season During the season she took a total of 90 free throw shots. Which, of the
adoni [48]

Answer:

  C.  22

Step-by-step explanation:

The problem statement tells you ...

  missed = 24.6% × 90

  = 0.246 × 90 = 22.14

The best estimate among the answers given is 22, choice C.

_____

<em>Comment on the problem statement</em>

The percentage given is supposedly computed from the number of shots attempted and missed <em>this season</em>. The ratio 22/90 would give a percentage rounded to 24.4%, not 24.6%.

24.4% of 90 is 21.96, closer to 22.

7 0
3 years ago
Use the shell method to find the volume of the solid generated by revolving the regions bounded by the curves and lines about th
RSB [31]

Answer:

The volume of the solid is:

\displaystyle\frac{19\pi}{6}

Step-by-step explanation:

See the graph of the region attached.

To find the intersection between the line and the parabola we set the equation equal to each other, and solve that quadratic equation by factorization:

x^2=9-8x\\x^2+8x-9=0\\(x+9)(x-1)=0\\x=-9,x=1

Since the region is the one for x\ge 0 then the intersection we are interested on is x=1 as it can also be seen in the graph.

Then we set the integral using shell method for revolving about the y-axis:

\displaystyle\int_a^b 2\pi\,x\,h(x)\,dx

Where h(x) is the height of the shell which here is the distance between the parabola and the line, so 8x-9-x^2 (since the line is on the top we subtract from it the parabola)

Then the integral becomes:

\displaystyle\int_0^1 2\pi\,x\,(8x-9-x^2)\,dx

Notice the limits of the integral are the x-axis (x=0) and the intersection of the parabola and the line that we found before (x=1)

Now, solving the integral:

Start by factoring the 2\pi and distributing the x:

=\displaystyle2\pi \int_0^19x-8x^2-x^3dx

Then use the basic rule to integrate:

=\displaystyle2\pi \left[\frac{9x^2}{2}-\frac{8x^2}{3}-\frac{x^4}{4}\right|_0^1

Then evaluate the antiderivative in the limits and subtract:

=\displaystyle2\pi\left[\frac{9}{2}-\frac{8}{3}-\frac{1}{4}-0\right]=\frac{19\pi}{6}

So the volume of the solid is \displaystyle\frac{19\pi}{6}

4 0
3 years ago
One of the values in this data set is 138.In this box Plot, what does this value mean ?
lesya [120]

Answer:

The value is the interquartile range which is 138.

Step-by-step explanation

Internet

8 0
3 years ago
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