The scale factor that was used to create triangle J’K’L’ is 1/3
<h3>How to determine the scale factor?</h3>
From the graph, we have the following highlights:
KL = 3
K'L' = 1
The scale factor (k) from JKL to J'K'L is calculated as:
Scale factor = K'L'/KL
This gives
k = 1/3
Hence, the scale factor that was used to create triangle J’K’L’ is 1/3
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Answer:
Answer:
you said you needed 22,23
22. y=7x-6
23. y=-x
Step-by-step explanation:
use math-way to put in the points
it explains for you
Step-by-step explanation:
Answer:
Step-by-step explanation:
the equation line passes through(-3,0)and (0,3) is : y=ax+b
a is the slope a = (3-0)/(0+3) = 1
so : y= x +b calculate b line passes through(-3,0)and (0,3)
x=0 y=3 : 3 = 0+b so b= 3
this equation is : y= x+3
Answer:
3rd graph.
Step-by-step explanation:
Roots of the equation are where the graph crosses the x axis. So the bottom left (3rd) graph is correct.
Answer:
3) 5
4) 8.2
5) 6.8
6)FG = 6.4
7) EF = 3.6
8)DF = 4.8
Step-by-step explanation:
From the attached triangle, using trigonometric ratio we can find ∠G as; tan^(-1) (6/8)
Thus, ∠G = 36.87°
Still using trigonometric ratios;
FG/8 = cos 36.87°
FG = 8 cos 36.87°
FG = 6.4
3) EF + FG = EG
Since EG is 10, mean of EF and FG = 10/2 = 5
4) mean of EG and FG = (10 + 6.4)/2 = 8.2
5) EF + FG = EG
Thus; EF = EG - FG
EF = 10 - 6.4
EF = 3.6
Mean of EG and EF = (10 + 3.6)/2 = 6.8
6) FG = 6.4
7) EF = 3.6
8) Using trigonometric ratio;
DF/8 = sin 36.87
DF = 8 × 0.6
DF = 4.8
