Ask question

Ask question

All categories

3 years ago

13

In math class a student scored 82 85 92 93 on 4 math test respectively what must the student score on a 5 test to earn an averag

e of a 90 across all 5 test

1 answer:

prisoha [69]3 years ago

7 0

They’re going to have to get a 98%

You might be interested in

Evaluate the expression for the given value of x.<br> 5x + 6 for x = 4

Brrunno [24]

If x=4, rewrite the equation which would be 5(4)+6

First you multiply 4 by 5 which would give you 20

Now put in the 6 in the equation

20+6

20+6=26

Therefore for the expression given the value of x would make your answer be 26

5 0

3 years ago

What is 10 4/5 - 2 1/5

Yuliya22 [10]

8 3/5
i hope i helped

4 0

3 years ago

Read 2 more answers

What is 18-4d equal to

jeka94

I think 14d hope this helps

6 0

3 years ago

Read 2 more answers

Summer looked at the formula for the Pythagorean Theorem, ashe said that it didn't matter which sides of a right triangle were a

irga5000 [103]

She is incorrect. It doesn’t matter what sides you label a or b but c matters. The longest side (the hypotenuse) is always c.

6 0

3 years ago

In triangle abc, cos A= -0.6. Find A and Tan A

Tresset [83]

Answer:

Part 1) $A=126.87^o$

Part 2) $tan(A)=-\frac{4}{3}$

Step-by-step explanation:

we have

$cos(A)=-0.6$

The cos(A) is negative, that means that the angle A in the triangle ABC is an obtuse angle and the value of the sin(A) is positive

The angle A lie on the II Quadrant

step 1

Find the measure of angle A

$cos(A)=-0.6$

using a calculator

$A=cos^{-1}(-0.6)=126.87^o$

step 2

Find the sin(A)

we know that

$sin^2(A)+cos^2(A)=1$

substitute the value of cos(A)

$sin^2(A)+(-0.6)^2=1$

$sin^2(A)=1-0.36$

$sin^2(A)=0.64$

$sin(A)=0.8$

step 3

Find tan(A)

we know that

$tan(A)=\frac{sin(A)}{cos(A)}$

substitute the values

$tan(A)=\frac{0.8}{-0.6}$

Simplify

$tan(A)=-\frac{4}{3}$

5 0

3 years ago