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2 years ago

Find the area of the triangle below.

Mathematics

1 answer:

lapo4ka [179]2 years ago

4 0

35 cm
using the formula a=1/2(b)(h), we can plug in 14 for b and 5 for h. This gives us 70, and when we multiply by 1/2 it leaves 35 cm.

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Help please asap!! will mark correct answer first brainliest! 25 POINTS.. FIRST SOLVE THE QUESTION WITH THE PICTURE THAN THE ONE

NemiM [27]

1. Eyeballing the data, the best fit will be pretty close to a line between the leftmost point and the rightmost point.

We estimate those points as (4,220) and (28,470)

The point point form for a line joining (a,b) and (c,d) is

(c-a)(y-b) = (d-b)(x-a)

(28 - 4)(y - 220) = (470 - 220)(x - 4)

24(y - 220) = 250(x-4)

24y - 5280 = 250x - 1000

24y = 250 x + 4280

y = (250/24) x+ (4280/24)

Approximately that's,

y = 10.4 x + 178

Answer: 4th choice, 10.4x + 180

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y = 10.4(48)+180 = 679.2

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4 0

3 years ago

Simultaneously x-2y=0 40-y=14

harkovskaia [24]

Answer:

x = 52, y = 26

Step-by-step explanation:

x - 2y = 0

40 - y = 14

(40 - 40) - y = 14 - 40

- y = -26

y = 26

x - 2(26) = 0

x - 52 = 0

x (- 52 + 52) = 0 + 52

x = 52

7 0

2 years ago

PLEASE SOMEONE HELP ME ASAP!!!!!ANYONE PLEASE!!!!

Natasha2012 [34]

Answer: B.$43.95

Explanation: 15% of $293 is $43.95

6 0

2 years ago

Read 2 more answers

A fraction becomes 4÷5 if 1 is added to both numerator and denominator. If, however, 5 is subtracted from both numerator and den

tia_tia [17]

Answer:

$\dfrac{7}{9}$

Step-by-step explanation:

$\dfrac{x+1}{y+1}=\dfrac{4}{5}\\\Rightarrow 5x-4y=-1$

$\dfrac{x-5}{y-5}=\dfrac{1}{2}\\\Rightarrow 2x-y=5$

Putting it in matrix form

$\begin{bmatrix}a_{1}&b_{1}\\a_{2}&b_{2}\end{bmatrix}{\begin{bmatrix}x\\y\end{bmatrix}=\begin{bmatrix}{c_{1}}\\{c_{2}}\end{bmatrix}\\\Rightarrow\begin{bmatrix}5 & -4\\2 & -1\end{bmatrix}\begin{bmatrix}x\\ y\end{bmatrix}=\begin{bmatrix}-1\\ 5\end{bmatrix}$

From Cramer's rule we have

$x=\dfrac{\begin{vmatrix}c_1 &b_1 \\ c_2 & b_2\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow x=\dfrac{\begin{vmatrix}-1 &-4 \\ 5 & -1\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1\end{vmatrix}}\\\Rightarrow x=\dfrac{1+20}{-5+8}\\\Rightarrow x=7$

$y=\dfrac{\begin{vmatrix}a_1 &c_1 \\ a_2 & c_1\end{vmatrix}}{\begin{vmatrix}a_1 &b_1 \\ a_2& b_2\end{vmatrix}}\\\Rightarrow y=\dfrac{\begin{vmatrix}5 &-1 \\ 2 & 5\end{vmatrix}}{\begin{vmatrix}5 &-4 \\ 2& -1 \end{vmatrix}}\\\Rightarrow y=\dfrac{25+2}{-5+8}\\\Rightarrow y=9$