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3 years ago

Someone please help me asap! i will give branniest!

Mathematics

1 answer:

lidiya [134]3 years ago

3 0

All you have to do is use ur calculator

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mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

$CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}$

Given:

$\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25$

Confidence level = 80%

$t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397$

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

$CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)$

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

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3 years ago

please help me and explain. what is the value of <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7By%7D%20" id="TexFormula1"

rosijanka [135]

$\frac{28}{x^2} = \frac{7}{xy}$
multiplying both sides by x^2
$28=\frac{7x^2}{xy}$
simplifying
$28= \frac{7x}{y}$
dividing by 7
$\frac{28}{7}= \frac{x}{y}$

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3 years ago

Please help I’m timed

kupik [55]

It’s the second one :)

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