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Rufina [12.5K]
3 years ago
11

Find the value of x.

Mathematics
2 answers:
antoniya [11.8K]3 years ago
8 0

Answer:

The value of x is 120°

Step-by-step explanation:

We should draw a line parallel to the given parallel lines and passes through the vertex of the measure x and divides it into two angles of measures x1 and x2, look at the attached figure

In the given figure

∵ The dashed line is parallel to the given line up

∴ The angle of the measure 70° and the angle x1 are alternate angles

∵ The alternate angles are equal in measures

∴ x1 = 70°

∵ The dashed line is parallel to the given line down

∴ The angle of the measure 50° and the angle x2 are alternate angles

∵ The alternate angles are equal in measures

∴ x2 = 50°

∵ x = x1 + x2

∴ x = 70 + 50

∴ x = 120°

∴ The value of x is 120°

Helen [10]3 years ago
7 0

Answer:

x= 120

Step-by-step explanation:

Alternated angles  are 50 and 70

Angles of a triangle sum 180

y+x (linear pair)

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The transformations done are option A. A reflection over the y-axis, then a reflection over the x-axis

Step-by-step explanation:

Step 1:

First, we plot the points of triangle ABC and A''B''C''.

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As part of their business promotional package, the Milwaukee Chamber of Commerce would like an estimate of the mean cost per mon
Morgarella [4.7K]

Answer:

a) 884-2.426\frac{50}{\sqrt{40}}=864.82    

884+2.426\frac{50}{\sqrt{40}}=903.179    

So on this case the 98% confidence interval would be given by (864.82;903.179)

b) For this case the upper bound of the confidence interval is lower than 950 so we don't have a significant evidence to conclude that the true mean is 950 per month

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=884 represent the sample mean

\mu population mean (variable of interest)

s=50 represent the sample standard deviation

n=40 represent the sample size  

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=40-1=39

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,39)".And we see that t_{\alpha/2}=2.426

Now we have everything in order to replace into formula (1):

884-2.426\frac{50}{\sqrt{40}}=864.82    

884+2.426\frac{50}{\sqrt{40}}=903.179    

So on this case the 98% confidence interval would be given by (864.82;903.179)

Part b

For this case the upper bound of the confidence interval is lower than 950 so we don't have a significant evidence to conclude that the true mean is 950 per month

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3 years ago
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