Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;
taking x=3+8i and substituting it in our equation we get:
(3+8i)^2-6(3+8i)+c=0
-55+48i-18-48i+c=0
collecting the like terms we get:
-55-18+48i-48i+c=0
-73+c=0
c=73
the answer is c=73
At first glance the answer seems like 3
u should draw it out
<span>f''(x) means function is of grade 1
f(x) = ax + b
f'(x) = a
f'(5) = 1 </span>⇒ a = 1
f(4) = -2
f(4) = 1×4 + b
-2 = 4 + b
b = -6
f(x) = x - 6
Answer:
D: 101, 135, 131, 99, 138, 136, 140
Step-by-step explanation:
edg2020 (do not get this confused with the question: "which set contains no outliers"
Answer:
5 students
Step-by-step explanation:
2/3 of 30 = 20 students
1/4 of 20 = 5 students