Question

Solving Quadratic Equations

Answer 1

Answer:

a) x= 5 or x= -3

b) x = -4 + $\sqrt{26}$ or -4 - $\sqrt{26}$

Step-by-step explanation:

a) $x^{2}$ - 2x - 15 =0

x = $\frac{-(-2) +\sqrt{(-2)^{2} - 4(1)(-15)}}{2(1)}$  or  $\frac{-(-2) -\sqrt{(-2)^{2} - 4(1)(-15)}}{2(1)}$

x= 5 or x=-3

b) $x^{2}$ + 8x - 10 =0

x = $\frac{-(8) +\sqrt{(8)^{2} - 4(1)(-10)}}{2(1)}$  or  $\frac{-(8) -\sqrt{(8)^{2} - 4(1)(-10)}}{2(1)}$

x = -4 + $\sqrt{26}$ or -4 - $\sqrt{26}$