Answer:
The expected value of the winnings for a single-ticket purchase is -$1.0016.
Step-by-step explanation:
The total number of tickets sold is, <em>N</em> = 1250.
Cost of one ticket is, $4.
Let <em>X</em> = amount of prize.
The prize distribution is as follows:
1 Grand price = $3000
1 Second prize = $450
10 Third prize = $25
The expected value <em>X</em> can be computed using the formula:

Compute the probability distribution of <em>X</em> as follows:
Prize Amount (X) P (X) x · P (X)
1 Grand prize $3000

1 Second prize $450

10 Third prize $25

No prize -$4

TOTAL 1.0000 -1.0016
Thus, the expected value of the winnings for a single-ticket purchase is -$1.0016.
X + y = 10
y = x + 2
so sub in x + 2 for y back into the first equation
x + y = 10
x + x + 2 = 10
2x + 2 = 10
2x = 10 - 2
2x = 8
x = 8/2
x = 4
y = x + 2
y = 4 + 2
y = 6
solution is : (4,6)
Area of Triangle = 1/2 * base * height
Area = 1/2 * 9 * 14 = 63
Area = 63 square inches