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2 years ago

Which equation BEST represents the line of best fit for the scatterplot?

Mathematics

2 answers:

Brrunno [24]2 years ago

7 0

Answer:

the answer is B) y = 2x + 2

velikii [3]2 years ago

6 0

Y=2x+2 describe the best fit.

first find x and y intercept of a line
x intercept where y=0 is x=-1 and y intercept where x=0 is y=2

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What is the value of x?

musickatia [10]

X = 7. Because both lines equal the same so it has to equal 75
11 x 7 = 77
77-2 = 75
X = 7

6 0

2 years ago

Read 2 more answers

System of equation x 3y=9 y=x-1

olga2289 [7]

8 0

3 years ago

What are the measures of angles B and C?

seropon [69]

Answer:

B. m<B = 65°; m<C = 115°

Step-by-step explanation:

First find the value of x:

3n + 20 = 6n - 25 (opposite bangles if a parallelogram are equal)

Collect like terms

3n - 6n = -20 - 25

-3n = -45

Divide both sides by -3

n = 15

✔️Find angle B:

m<B = 3n + 20

Plug in the value of n

m<B = 3(15) + 20

m<B = 45 + 20

m<B = 65°

✔️Find angle C:

m<C = 180 - m<B (consecutive angles of a parallelogram are supplementary)

m<C = 180 - 65

m<C = 115°

4 0

2 years ago

Read 2 more answers

Which is an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12?

Bond [772]

Answer:

An equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

$y=-\frac{1}{5}x+\frac{13}{5}$

Step-by-step explanation:

Given the equation

$5x - y = 12$

converting the line into the slope-intercept form y = mx+b, where m is the slope

$-y = 12-5x$

$y = 5x-12$

The slope of the line = m = 5

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

Therefore, the slope of new line = – 1/m = -1/5 = -1/5

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope of the line and (x₁, y₁) is the point

substituting the slope of new line = -1/5 and (-2, 3)

$y-y_1=m\left(x-x_1\right)$

$y-3=-\frac{1}{5}\left(x-\left(-2\right)\right)$

$y-3=-\frac{1}{5}\left(x+2\right)$

Add 3 to both sides

$y-3+3=-\frac{1}{5}\left(x+2\right)+3$

$y=-\frac{1}{5}x+\frac{13}{5}$

Therefore, an equation of the line passing through (-2, 3) and perpendicular to the line 5x - y = 12 will be:

$y=-\frac{1}{5}x+\frac{13}{5}$

5 0

3 years ago

L= 9.25 cm; A = 55.5 cm square

miv72 [106K]

Answer:

shhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Step-by-step explanation:

4 0

2 years ago