<em><u>The least amount of money you would need to invest per month is; $335</u></em>
<em><u>The anticipated rate of return on your investments is; 7%</u></em>
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- Amount to have been saved at the end of 10 years ≥ $40,000
Number of years of savings = 10 years.
- We want to find out the least amount to be invested per month.
There are 12 months in a year. Number of months in 10 years = 10 × 12 = 120 months.
- Thus, amount to be saved monthly = 40000/12 = $333.33
- Since the minimum amount he wants to save after 10 years is $40000, then we need to approximate the monthly savings in order.
Thus;
Monthly savings ≈ $335
- Now, for the anticipated rate of return on the investment, we know from S & P's that the benchmark on good rate of return for investment is a minimum of 7%.
- From online calculator, the worth of the investment after 10 years based on 7% rate of return yearly would be $57626.
Read more at; brainly.com/question/9187598
Answer:
The correct solution is C (x> -2)
5d=470:
in this case we have to divide both sides by 5:
d=94
8a=47:
in this case we have to divide both sides by 8:
a=5.875
as a general rule, if you want to find out a value of a in
ab=c
you have to divide both sides of the equation by b (if it's not zero); then you will have left:
a=c/b
and if you calculate c/b, this will give you the answer
T is the cost of the table. B is the cost of a bench.
b+t=652
b+98=t
t-98+t=652
2t=554
t=277
b=375
Hope this helps!
A = B+32
B = 5C
A = 5C+32
C has d dollars so replace d for c
A = 5d+32
