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Zielflug [23.3K]
2 years ago
5

Gavin rolls a fair dice 48 times. How many times would Gavin expect to roll an even number?

Mathematics
1 answer:
pantera1 [17]2 years ago
6 0

Answer: The number of times Gavin expect to roll an even number =24

Step-by-step explanation:

Given: Numbers of a fair dice = 1, 2, 3, 4, 5, 6

even numbers = 2, 4, 6

odd numbers = 1, 3, 5

Probability of getting an even number = \dfrac{3}{6}=\dfrac12

If Gavin rolls a fair dice 48 times.

Then, the number of times Gavin expect to roll an even number = 48\times\dfrac12=24

Hence, the number of times Gavin expect to roll an even number =24

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a_0=15,\:\quad a_n=2

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-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

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2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

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2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

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\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

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