Based on the Ksp calculations, the molar solubility of AgCl in 0.500 M of NH₃ is equal to 2.77 × 10⁻² M.
<h3>How to determine the molar solubility.</h3>
First of al, we would write the properly balanced chemical equation for this chemical reaction:
AgCl(s) ⇆ Ag⁺(aq)+ Cl⁻(aq) Ksp = 1.8 × 10⁻¹⁰
AgCl(s) + 2NH₃(aq) ⇆ Ag(NH₃)₂⁺(aq) Kf = 1. 7 × 10⁷
<u>Given the following data:</u>
- Ksp of AgCl = 1.8 × 10⁻¹⁰
- Concentration of NH₃ = 0.500
- Kf of ag(nh₃)₂⁺ = 1.7 × 10⁷
K = Ksp × Kf
K = 1. 80 × 10⁻¹⁰ × 1.7 × 10⁷
K = 3.06 × 10⁻³
Mathematically, the Ksp for the above chemical reaction is given by:
![K=\frac{ [Ag(NH_3)_2^{+}][Cl]}{[NH_3]^2}\\\\3.06 \times 10^{-3}=\frac{[x][x]}{0.50^{2 }}\\\\3.06 \times 10^{-3}=\frac{x^2}{0.25}\\\\x^2 = 7.65\times 10^{-4}\\\\x=\sqrt{7.65\times 10^{-4}}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%20%5BAg%28NH_3%29_2%5E%7B%2B%7D%5D%5BCl%5D%7D%7B%5BNH_3%5D%5E2%7D%5C%5C%5C%5C3.06%20%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B0.50%5E%7B2%20%7D%7D%5C%5C%5C%5C3.06%20%5Ctimes%2010%5E%7B-3%7D%3D%5Cfrac%7Bx%5E2%7D%7B0.25%7D%5C%5C%5C%5Cx%5E2%20%3D%207.65%5Ctimes%2010%5E%7B-4%7D%5C%5C%5C%5Cx%3D%5Csqrt%7B7.65%5Ctimes%2010%5E%7B-4%7D%7D)
x = 2.77 × 10⁻² M.
Read more on molar solubility here: brainly.com/question/3006391
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Answer:
All of above
Explanation:
Firstly, the kind of data that is provided to you determines what kind of information you can extract from it because of the determinants it is covering. A good set of data shows us how each child is developing and what are the external or internal factors that are inhibiting or enhancing his growth.
This is a way of knowing what needs changing around them. It can also tell us how effective the mode of instruction and the environment around them is.
A method which would quickly reveal if the solution was saturated or unsaturated is to add heat to the solution and stir.
<h3>What is solubility?</h3>
Solubility can be defined as a terminology that describes how readily a chemical substance (compound) can be dissolved in a solvent to form a solution, which may either be saturated or unsaturated.
In Chemistry, a chemical substance (compound) is considered to be soluble if it dissolves completely in a solvent such as water.
In this experiment, a method which can be used by the student to quickly reveal if the solution was saturated or unsaturated is to add heat to the solution and stir because it will increase the rate in which it dissolves and settles at the bottom.
Read more on solutions here: brainly.com/question/23946616
