FIRST LAW Unless otherwise acted upon, an object in motion stays in motion; an object at rest stays at rest.
2 answers:
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Answer:
X has travelled 4 times as far as Y
X is moving 2 times as fast as Y
Explanation:
Because x=1/2at²(get rid of the first portion of x=vt+1/2at² because initial v is 0 which multiplies to 0). If the acceleration is set to for example 10 (keep this constant for both X and Y) and we use t=1 and t=2 for time (as the time travelled of X is twice that of Y). Plugging this into the equation, at t=1, x=4. At t=2, x=20. 20 is four times greater than 5, so X has travelled 4 times as far as Y.
To find the difference in speed between the two objects, use the equation . Since the initial velocity is 0, that part can just be removed from the equation. With v=at, it is easy to see that if the time plugged in is twice for one than the other (and the acceleration is the same for both), the final result will be twice of the other as well. For example: If the acceleration is 10 again for both, then v=10t. If t is 1, the velocity is 10. If t is 2, the velocity is 20.
The sum of the two numbers is equal to 70.
- Let the first number be x.
- Let the second number be y.
In this exercise, you're required to find two numbers by translating the word problem into an algebraic expression and then solving for the unknown variables (x and y).
Translating the word problem into an algebraic expression, we have;
Two numbers differ by 8:
....equation 1.
The product of the two numbers is 713:
....equation 2.
To calculate the sum of the two numbers:
First of all, we would solve for each of the unknown variables (x and y).
From eqn. 1, we have:
....equation 3.
Substituting eqn. 3 into eqn. 2, we have:
Solving the quadratic equation by factorization, we have:
y = -23 or 31.
For the value of x, when y = 31:
x = 39
Now, we can calculate the sum of the two numbers:
Read more on word problems here: brainly.com/question/13170908