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makkiz [27]
3 years ago
11

rose is taking her younger sister to see an animated film about magical singing creatures. her family lives outside the city, so

she has to drive a long way to get to the theater. rose has brought some money to buy her sister some fresh, hot popcorn. when she picks up the popcorn, rose is burned by a splash of hot oil.
SAT
1 answer:
valentinak56 [21]3 years ago
7 0

Answer:66.7 23

Explanation:

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Compare these two fractions: 6/10 and 4/6 * 5 points 6/10 > 4/6 4/6 > 6/10 4/6 = 6/10
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I mgmgmgjvjgjgjgkgkgkvngjfnfnfkgkg

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Which of the following is true about RNA
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One of the bases of DNA is replaced by Uracil. B is the correct option.

<h3>Features of RNA</h3>
  • RNA has ribose sugars, unlike DNA which has deoxyribose sugars
  • It contains Uracil instead of Thymine in DNA
  • RNA is single-stranded, unlike DNA which is double-stranded
  • There are 3 forms, tRNA, mRNA, and rRNA.

More on RNA can be found here: brainly.com/question/25979866

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A It contains adenine paired to thymine

B One of the bases from DNA is replaced by uracil

C It contains the sugar deoxyribose

D Its nucleotides contain twice as many phosphate groups as DNAs nucleotides

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1 year ago
A small office supply store sells paper clips in packs of 100 and packs of 250. If the store has 84 packs of paper clips in stoc
sveta [45]
Let x and y be the number of packs with 100 and 250 paper clips, respectively. The system of linear equations that would best represent the given is
                                     x + y = 84
                                    100x + 250y = 12,300

The values of x and y from the equations are 58 and 26, respectively. If a person buys half of the packs of 250 paper clips,
                              n = (0.5)(250)(26) = 3250

Thus, a person bought 3250 paper clips. 
3 0
3 years ago
A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin
Alekssandra [29.7K]

The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

  • 131.6 N/C
  • 12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}

Which gives;

\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C

\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C

Which gives;

\vec{E}_1 = \mathbf{21.6 \, N/C  \cdot \hat x +  28.8 \, N/C \hat y}

\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C

Therefore;

\vec  {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)

\vec  {E} = \mathbf{\left( -128.4 \, N/C  \right) \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)}

The magnitude of the net electric field is therefore;

E = \sqrt{(-128.4^2 + 28.8^2)} ≈ 131.6

  • The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>

(b) The direction of the net electric field at the origin.

  • The \ direction \ is \ arctan \left(\dfrac{28.8}{-128.4} \right) \approx \underline{ 12.6^{\circ}} \ above \ the \ negative \ x-axis

Learn more about electric field strength here:

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it should be <u>D. Big business </u>

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