Find the length of the side C in the triangle ABC where a=4.7 b=10.21 and ACB=105.3
1 answer:
9514 1404 393
Answer:
(d) 12.3
Step-by-step explanation:
From the Law of Cosines, you can solve for c:
c = √(a² +b² -2ab·cos(C)) = √(22.09 +104.2441 -95.974cos(105.3°))
c ≈ √151.659 ≈ 12.31499
Side c is about 12.3 units long.
You might be interested in
Answer:
a:false
b:true
c:true
Step-by-step explanation:
a:the sum of all the probabilities in the distribution must be equal to one.
My apologies if any are wrong.
Answer:
£45
Step-by-step explanation:
Given data
P= £300
R=5%
T= 3 years
SI= PRT/100
substitute
SI= 300*5*3/100
SI=4500/100
SI= £45
Hence the interest is £45
Answer:
a
Step-by-step explanation:
the line model shows 2 halfs of 4/10
Answer:
-1/2
Step-by-step explanation:
y = mx + c is the standard form of the equation where m is slope. Comparing the question to the equation we get
m = -1/2
Answer:
Confusion
Step-by-step explanation:
what the heck are you asking?
