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s344n2d4d5 [400]
3 years ago
14

Let g be the function given by g(x)=√ 1−sin2x. Which of the following statements could be false on the interval 0≤x≤π ?

Mathematics
1 answer:
zysi [14]3 years ago
6 0

Answer:

yooooooooooooooooooooooooo

Step-by-step explanation:

yesirskiii\

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The swimming pool at Spring Valley High School is a rectangle with a width of 75 meters and a length of 35 meters. Around the pe
stealth61 [152]
Same as before

total=(2w+75)(2w+35)=4w²+220w+2625

pool=75 times 35=2625

minus pool from total
4w²+220w+2625-2625=4w²+220w
4 0
3 years ago
How do you solve this?
puteri [66]

Answer:

Width: 7

Length: 14

Step-by-step explanation:

The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let x represent the width.

Since the length is 7 feet longer, we can represent the length by x+7.

Now that we have our values for the length and the width we can multiply them together to find our area.

(x)(x+7)=x^{2} +7x

Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.

(x+7)(x+14)

And multiply our area by 3.

3(x^{2} +7x)

set these equal to each other to find your new equation.

(x+7)(x+14)=3(x^{2} +7x)

Now you need to solve for x. To do this first muliply (x+7) and (x+14).

(x+7)(x+14)=\\x^{2} +14x+7x+98=\\x^{2} +21x+98

Then multiply 3(x^{2} +7x)

3(x^{2} +7x)=\\3x^{2} +21x

Now you can begin solving for x.

x^{2} +21x+98=3x^{2} +21x

Subtract x^{2} from both sides.

21x+98=2x^{2} +21x

Subtract 21x from both sides.

98=2x^{2}

Divide by 2.

49=x^{2}

And finally take the sqaure root of both sides.

\sqrt{x^{2} }=\sqrt{49}\\x=7

Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 <em>and</em> -7, in this case we <em>only </em>get +7.

Now that we have the value of x, we can plug it into our original values.

For width we simply get 7.

For length we get 7+7=14

To check our answer we cna multiply 7 by 14 to get 98. Then we can add 7 to our length and width to get 14 and 21. Multiply these together and we get 294. 294 divided by 3 is 98, proving our answer correct.

7 0
3 years ago
Please help 5x^2+21x+4
SVEN [57.7K]

Answer:

(5x+1) (x+4)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
In an experiment, a ball is drawn from an urn containing 12 purple balls and 13 green balls. If the ball is purple, two coins ar
UNO [17]

Answer:

4 elements of the sample space will have a purple ball

There are 10 elements altogether

Step-by-step explanation:

Probability is given by number of possible outcomes ÷ number of total outcomes

Number of purple balls = 12, number of green balls = 13, total number of balls = 12+13 = 25

Probability (a ball drawn is purple) = 12/25

If a purple ball is drawn, two coins are tossed

1 coin has 2 elements

2 coins have 2×2 = 4 elements

Probability (a ball drawn is not purple) = 1 - 12/25 = (25-12)/25 = 13/25

If a ball drawn is not purple, three coins are tossed

1 coin has 2 elements

3 coins have 3×2 = 6 elements

Total elements = 4 + 6= 10 elements

5 0
3 years ago
. Consumer Awareness In 1986, the average cost of a new midsize four-door sedan was $9000. In 1991, the average cost was $12,000
eduard

<u>Answer-</u>

\boxed{\boxed{y=9000(1.0592)^x}}

<em>And cost of a car in the year 2000 will be </em><em>$20134.18</em>

<u>Solution-</u>

Let's assume,

x = number of years after 1986

y = average cost of sedan in dollar

The exponential model that will model the scenario will be in the form of,

y=ab^x

where a and b are constants

As given that, in 1986 average cost of sedan was $9000 and in 1991 average cost of sedan was $12000

So, the points (0, 9000) and (5, 12000) will satisfy or lie on the exponential curve.

Putting (0, 9000) in the equation,

\Rightarrow 9000=ab^0

\Rightarrow a\times 1=9000

\Rightarrow a=9000

Now, the equation becomes y=9000b^x

Putting (5, 12000) in this equation,

\Rightarrow 12000=9000b^5

\Rightarrow b^5=\dfrac{12000}{9000}

\Rightarrow b=\sqrt[5]{\dfrac{4}{3}}

\Rightarrow b=1.0592

Putting the values,

y=9000(1.0592)^x

As we have to calculate the cost of sedan in 2000, so putting x=14(as 2000-1986=14),

y=9000(1.0592)^{14}=20134.18

Therefore, cost of a car in the year 2000 will be $20134.18

8 0
3 years ago
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