All categories

3 years ago

Identify the function as either a constant, direct variation, absolute value or greatest integer function f (x)=-4

1 answer:

7 0

Answer: Constant

No matter what the input x is, the output f(x) is going to be -4. Therefore, the output is constant.

Note: f(x) can be interchanged with y. So we can say y = -4.

You might be interested in

I don't under stand what is wrong.

MAXImum [283]

Answer:

In the first step, there is an issue when distributing the -3 to the terms inside of the parentheses. When multiplying the -3 to the -5, you would get an answer of +15, not -15.

The full correct process is:

(4m + 9) - 3(2m - 5) = 4m + 9 - 6m + 15

= 4m - 6m + 9 + 15

= -2m + 24

4 0

2 years ago

A car begins to depreciate at a rate of 24.9% annually as soon as it is driven off the lot. If a car was purchased for 26,500; h

STatiana [176]

Answer:

13197

Step-by-step explanation:

You have to do 24.9*2 and then find that percent of 26500

6 0

3 years ago

How do you complete this task?

Assoli18 [71]

Answer:

-3/2

Step-by-step explanation:

y=mx +b

where m is the slope and b is the y intercept

we just need to rewrite 3x+2y+18=0 to look like that

We need to get y by itself

3x+18= -2y

we need y to be positive and to have no number in front of it (no coeficcent)

y= -3/2x-9

the slope is therefore -3/2

3 0

3 years ago

Read 2 more answers

Multiply 16.852 × 0.86

Leni [432]

Answer:

14.49272 or 14.5 (when rounded)

Step-by-step explanation:

5 0

3 years ago

The equation 2x^2 – 8x = 5 is rewritten in the form of 2(x – p)^2 + q = 0. what is the value of q?

QveST [7]

Answer:

q = -13

Step-by-step explanation:

The given equation is:

$2x^{2}-8x=5$

Taking 2 as common from left hand side, we get:

$2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5$

The square of difference is written as:

$(a-b)^{2}=a^2 - 2ab + b^{2}$ Equation 1

If we compare the given equation from previous step to formula in Equation 1, we note that we have square of first term(x), twice the product of 1st term(x) and second term(2) and the square of second term(2) is missing. So in order to complete the square we need to add and subtract square of 2 to right hand side. i.e.

$2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0$

Comparing the above equation with the given equation:

$2(x-p)^{2}+q=0$ , we can say:

p = 2 and q= -13

6 0

3 years ago