1. You notice that you only have 13 pound of cheese and 34 cup of milk. How much

In the activity graph below, where time is measured in hours, what is the minimum time to ﬁnish the project?

Andrew [12]

I believe it is D.
On the very bottom if you just go straight across then it would be 7+3+8 which is 18.

7 0

3 years ago

Isi drilled a hole that is 5/9 inch wide.she has a screw that is 5/6 inch wide.is the hole wide enough to fit the screw

koban [17]

NO the screw is to big to fit

The variable in non simplified form will be

5/9 is 10/18

5/6 is 15/18

Since 5/6 is larger the screw will not be able to fit in a smaller hole.

Hope this helped!

5 0

3 years ago

PLZ HELP ME ASAP PLZ PLZ PLZ!!!!! I NEED LOTS OF HELP!!! I USED 40 POINTS

cupoosta [38]

First, some defintions
reciprocals are like a/b and b/a or 5/1 and 1/5

remember, $\frac{\frac{a}{b}}{\frac{c}{d}}=(\frac{a}{b})(\frac{d}{c})=\frac{ad}{bc}$

john's fraction is reciprocal of sarah's
john=a/b
sarah=b/a

david multiplies his by sarah and gets 12/35
(b/a)(david)=12/35

multplies his number by john and gets 12/35
(a/b)(david)=15/7

hmmm

(b/a)(david)=12/35 and
(a/b)(david)=15/7

if we divide them then we do
$\frac{(\frac{b}{a})(david)}{(\frac{a}{b})(david)}=\frac{\frac{12}{35}}{\frac{15}{7}}=$
$\frac{\frac{b}{a}}{\frac{a}{b}}=\frac{\frac{12}{35}}{\frac{15}{7}}=$
$(\frac{b}{a})(\frac{b}{a})=(\frac{12}{35})(\frac{7}{15})=$
$\frac{b^2}{a^2}=\frac{84}{525}=$
$\frac{b^2}{a^2}=\frac{4}{25}$
square root both sides
$\frac{b}{a}=\frac{2}{5}$

therefor
b=2 and a=5

john's number is a/b=5/2
sarah's number is 2/5

david, hmm

sarah times david=12/35
2/5 times david=12/35
times both sides by 5/2
david=60/70
david=6/7

check other

john times david=15/7
5/2 times 6/7=15/7
30/14=15/7
15/7=15/7
true

sarah's favorite number is 2/5
john's favorite number is 5/2
david's favorite number is 6/7

6 0

3 years ago

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

Verizon [17]

Answer:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

Step-by-step explanation:

We know the following info:

$\bar X_1 = 21.9$ sample mean for group 1

$\bar X_2 = 19.8$ sample mean for group 2

$s_1 = 3.4$ sample standard deviation for group 1

$s_2 = 3.5$ sample standard deviation for group 2

$n_1 = 200$ sample size group 1

$n_2 = 200$ sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

Now we just need to find the critical value. The confidence level is 0.95 then the significance is $1-0.95 =0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by: