The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
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Answer:
3 79/100
Step-by-step explanation:
Answer:
x=5
Step-by-step explanation:
-5x+6(5x-18)=17
-5x+30x-108=17
25x-108=17
25x=17+108
25x=125
x=5
Answer:
y=x+4
Step-by-step explanation:
2y=2x+4 simplifies down to y=x-2. Since the two lines are parallel, they have to have the same slope, but different y-intercepts. This means that we just have to find the y-intercept that will allow our line to pass through (-5, -1).
If we input the coordinates into what of our equation we have thus far (y=x+b), we just have to find what b needs to equal to make the equation true.
-1=-5+b -1=-5+4
b = 4 -1=-1
Answer:
x = 50
Step-by-step explanation:
Since MNP is a tangent to the circle at N, then
∠ ONP = 90° , so
∠ ONL = 90° - 55° = 35°
OL = ON ( both radii of the circle )
Thus Δ ONL is isosceles and the base angles are congruent
∠ OLN = ∠ ONL = 35°
JKLN is a cyclic quadrilateral whose opposite angles are supplementary, that is
∠KJN + ∠ KLN = 180 , substitute values
95 + 35 + x = 180
130 + x = 180 ( subtract 130 from both sides )
x = 50
