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eduard
3 years ago
11

You are serving bratwurst and hamburgers at your annual picnic. You want at least three bratwursts or hamburgers for each of you

r 35 guests. Bratwursts cost $1.3 each and hamburgers $1.2 each. Your budget is $150
Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0
1.3*3=3.90
3.90*35=136.50
136.50 is all you need to provide at least three of the most expensive items.
You still have 13.50 left over
ipn [44]3 years ago
6 0
If you buy 3 bratwursts for each guest that would be 1.3*3*35 = 136.5 which will fit your budget no problem.
If you buy 3 hamburgers for each guest that would be 1.2*3*35 = 126 which also fits your budget.
Whichever one you decide to buy will be no problem for that budget.
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Glenn needs to cut pieces of ribbon that are each 1 meter long to make ribbon key chains. If he has 6 pieces of ribbon that are
Jet001 [13]

Answer:

2/3

Step-by-step explanation:

Glenn needs to cut pieces of ribbon that are each 1 meter long to make ribbon key chains. If he has 6 pieces of ribbon that are each 1 dekameter long, how many 1−meter pieces of ribbon can he cut?

1 decametre = 10 metres

Hence,

10 meters = 6 pieces of ribbon

1 meter = x pieces

Cross Multiply

10x = 6

x = 6/10

x = 2/3 (1 meter pieces of ribbon)

6 0
3 years ago
Can somebody step by step explain how to solve this problem??<br><br> (3x^2y)(-7xy^3)
charle [14.2K]

Answer:

\boxed{\bold{-21x^3y^4}}

Explanation:

[ Step One ] Remove Parenthesis: (a) = a

\bold{-3x^2y\cdot \:7xy^3}

[ Step Two ] Multiply: \bold{3\cdot \:7=21}

\bold{-21x^2xy^3y}

[ Step Three ] Apply Exponent Rule \bold{\:a^b\cdot \:a^c=a^{b+c}: \ x^2x=\:x^{2+1}=\:x^3}

\bold{-21x^3y^3y}

[ Step Four ] Apply Exponent Rule: \bold{y^3y=\:y^{1+3}=\:y^4}

\bold{-21x^3y^4}

[ \boxed{\bold{Final \ Answer}} ]

➤ \bold{-21x^3y^4}

\boxed{\bold{Mordancy}}

5 0
3 years ago
Read 2 more answers
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
Keith_Richards [23]

Answer:

8.0 seconds to the nearest tenth,

Step-by-step explanation:

h=-16t^2 +vt + c.

-16t^2 + 116t + 101 = 0

t =  [ -116 + /- √(116^2 - 4*-16*101) ] / (-32)

t = (-116 +/- √19920) / (-32)

t = -0.79, 8.036  (we ignore the negative root)

The time in flight = 8.036 seconds.

4 0
3 years ago
Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0
3 years ago
An angle is created from points C, A, and B with vertex A. An arc is drawn from point A and intersects rays AC and AB. The inter
Minchanka [31]

Answer:

Bisecting an angle ⇒ answer a

Step-by-step explanation:

* <em>Lets revise the steps of bisecting an angle</em>

- <em><u>How to construct a bisector of angle XYZ</u></em>

1. Open the compass to any width, and place its pin at the angle’s

   vertex Y and draw an arc cuts the two rays of the angle YX and YZ

   at two points M and N respectively

2. Open the compass to another width and place its pin at M and draw

    an arc between the two rays YX and YZ

3. Without changing the width of the compass place its pin at N and

   draw another arc intersects the arc from M at point Q

4. Join YQ which is the bisector of angle XYZ

* <em>Now lets compare these steps by the steps of the question</em>

∵ The vertex of the angle ABC is A represented by Y

∵ The rays of the angle AC and AB represented by YX and YZ

∵ Points D , E represented by points M , N

∴ The construction is " Bisecting an angle "

7 0
3 years ago
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