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Semmy [17]
2 years ago
11

in preparation for a party, brant is putting desserts onto platters. the chocolate cake is cut into 15 pieces and the cheesecake

is cut into 6 pieces. if he wants to prepare identicle platters without having any cake left over, what is the greatest number of platters he can prepare?
Mathematics
1 answer:
marishachu [46]2 years ago
8 0

Answer:

The greatest number of platters he can prepare is 3.

Step-by-step explanation:

Given : In preparation for a party, brant is putting desserts onto platters. the chocolate cake is cut into 15 pieces and the cheesecake is cut into 6 pieces. if he wants to prepare identical platters without having any cake left over.

To find : What is the greatest number of platters he can prepare?

Solution :

The greatest number of platters he can prepare is given by finding the GCF of 15 and 6.

Factoring the numbers,

6=2\times 3

15=3\times 5

The GCF is the greatest common factor.

GCF(6,15)=3

Therefore, the greatest number of platters he can prepare is 3.

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YZ = WZ  

YZ = 38

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A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in
Oksi-84 [34.3K]

Answer: The concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

                               Compound X             Compound Y

272                               16400                            3870

327                                3990                             6420

So, our equations becomes

16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191

By solving these two equations, we get that

C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}

Hence, the concentration of X is 7.13582\times 10^{-6} and the concentration of Y is 2.53159\times 10^{-5}.

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