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stiv31 [10]
3 years ago
13

Can you answer this

Mathematics
1 answer:
scoray [572]3 years ago
4 0
I did know is understandable is the web in math?
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What are some ways you can break apart 7x9 using distributive property
Tresset [83]
7+7+7+7+7+7+7+7+7=63 9+9+9+9+9+9+9=63 9×6=54 54+9=63
7 0
3 years ago
Read 2 more answers
WORTH 20 POINTS HELP
vfiekz [6]

Below represents the proof that the quadrilateral QRST is a parallelogram

<h3>How to prove that QRST is a parallelogram?</h3>

The coordinates are given as:

Q = (-1,-1)

R = (2,9)

S = (-4,5)

T = (-7,-5)

Calculate the length of each side using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

So, we have:

QR = \sqrt{(-1 - 2)^2 + (-1 -9)^2} = \sqrt{109}

RS = \sqrt{(-4 - 2)^2 + (5 - 9)^2} = \sqrt{52}

ST = \sqrt{(-7 + 4)^2 + (-5 - 5)^2} = \sqrt{109}

TQ = \sqrt{(-7 + 1)^2 + (-5 + 1)^2} = \sqrt{52}

The above computations show that opposite sides are equal.

Next, we determine the slope of each side using:

m = \frac{y_2 -y_1}{x_2 -x_1}

So, we have:

QR = \frac{9 + 1}{2 + 3} = \frac{10}3

RS = \frac{5-9}{-4 - 2} = \frac{2}3

ST = \frac{5+5}{-4 + 7} = \frac{10}3

TQ = \frac{-5+1}{-7 + 1} = \frac{2}3

The above computations show that opposite sides are parallel, because they have equal slope

Hence, the quadrilateral QRST is a parallelogram

Read more about parallelograms at:

brainly.com/question/3050890

#SPJ1

6 0
2 years ago
5) Use the diagram and the Pythagorean Theorem to find the EXACT area of square ABCD.
dimaraw [331]
I think the answer is C
8 0
2 years ago
To solve a one-step equation, you must _____<br> the variable.
krek1111 [17]

Answer:

Isolate.

Step-by-step explanation:

To solve a one-step equation, you must isolate the variable.

For example,

3x = 9.

You must isolate x, which just means you have to get x by itself.

Divide by 3 on both sides to get x by itself.

x = 3.

The answer to this question is isolate.

8 0
3 years ago
How to find the angle of a triangle with 3 sides?
Molodets [167]

Explanation:

The Law of Cosines specifies the relationship between the three sides of a triangle and any one of the angles. If the sides are designated a, b, and c, and the angle opposite side c is C, then it tells you ...

  c² = a² + b² -2ab·cos(C)

This relationship can be used to find any and all angles, given the three sides of a triangle. Or, having found one angle using the Law of Cosines, the others can be found using the Law of Sines:

  sin(A)/a = sin(B)/b = sin(C)/c

_____

Typically, inverse functions are required. That is, from the Law of Cosines, ...

  C = arccos((a² +b² -c²)/(2ab))

And from the Law of Sines, ...

  A = arcsin(a/c·sin(C))

  B = arcsin(b/c·sin(C))

_____

<em>Note on solving triangles</em>

It often works best to make use of exact values where possible. It is also a good idea to start with the longest side/largest angle. Of course, once you have two angles the other can be found as the supplement of their sum.

8 0
3 years ago
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