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Brut [27]
3 years ago
8

Yes its me the one iwth 55 zeroes

Mathematics
1 answer:
kvasek [131]3 years ago
5 0

Answer:

thanks

Step-by-step explanation:

50389203029138213/932810392748392748329473

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Community college students survey students at their college and ask, "Have you met with a counselor to develop an educational pl
UkoKoshka [18]

Answer:

The 90% CI for p is (0.53, 0.83)

Step-by-step explanation:

We have to develop a 90% confidence interval for the proportion of all students at the college that have met with a counselor to develop an educational plan.

We have a sample of size 25, where the sample proportion is:

p=X/n=17/25=0.68

The critical value of z for a 90% CI is z=1.645.

The margin of error is then:

E=z\cdot\sqrt{\dfrac{p(1-p)}{n}}=1.645*\sqrt{\dfrac{0.68*0.32}{25}}=1.645*\sqrt{0.008704}=1.645*0.093\\\\\\E=0.15

Then, the lower and upper bound of the confidence interval are:

LL=\hat p-E=0.68-0.15=0.53\\\\UL=\hat p+E=0.68+0.15=0.83

The 90% CI for p is (0.53, 0.83)

8 0
3 years ago
Please answer attached Parallel lines with Multiple transversals
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Answer:

Step-by-step explanation:

3 0
3 years ago
If bookstore ABC Books determines it is going to sell books at its profit-maximizing price of $19 in a market facing monopolisti
Nesterboy [21]

Answer:

$8.

Step-by-step explanation:

See attached picture.

6 0
3 years ago
You have a coin that is not weighted evenly and therefore is not a fair coin. Assume the true probability of getting heads when
Alexandra [31]

Answer:

X \sim Binom(n=157, p=0.52)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want this probability:

P(X

And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

And we got 0.1633

The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

np=157*0.52=81.64  \geq 10

n(1-p)=157*(1-0.52)=75.36 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=157*0.52=81.64

\sigma=\sqrt{np(1-p)}=\sqrt{157*0.52(1-0.52)}=6.26

We want this probability:

P(X

And using the continuity correction we have this:

P(X

We can use the z score given by this formula Z=\frac{x-\mu}{\sigma}.

P(X< 76.5)=P(\frac{X-\mu}{\sigma}< \frac{76.5-81.64}{6.26})=P(Z < -0.821)=0.206

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=157, p=0.52)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want this probability:

P(X

And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

And we got 0.1633

The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

np=157*0.52=81.64  \geq 10

n(1-p)=157*(1-0.52)=75.36 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=157*0.52=81.64

\sigma=\sqrt{np(1-p)}=\sqrt{157*0.52(1-0.52)}=6.26

We want this probability:

P(X

And using the continuity correction we have this:

P(X

We can use the z score given by this formula Z=\frac{x-\mu}{\sigma}.

P(X< 76.5)=P(\frac{X-\mu}{\sigma}< \frac{76.5-81.64}{6.26})=P(Z < -0.821)=0.206

4 0
4 years ago
Round 243.583 to the nearest tenth *
Nastasia [14]

Answer: 243.6

Step-by-step explanation:

For us to solve the question and round off 243.583 to the nearest tenth. First, we need to look at the number beside the tenth number which is 8.

Since 8 is more than 4, we simply add 1 to the tenth number which implies that we add 1 to the number in tenth place which is 5. Adding one means the number change to 6. Therefore, rounding 243.583 to the nearest tenth will be 243.6.

4 0
3 years ago
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