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dexar [7]
3 years ago
9

1. x² + 2xy – 7 xy + 4y?Input your answer here:​

Mathematics
1 answer:
viktelen [127]3 years ago
6 0

collect the like terms:

Solution: x^2-5xy+4y

P.S

get the photo math app. :)

Hope that helps.

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HELP PLEASE IM STUCK
Ludmilka [50]
A. y=180-15m
m is the number of months. 180 is the amount owed after the down payment was made.
B. X intercept (12,0)
Y intercept (0,180)
X intercept is the number of months until the tv is paid off. The y intercept is the amount owed after the down payment is made. How much they will be making payments on.
32. 5x + 15
6 0
3 years ago
1. Thom has a scale model of his car. The
MariettaO [177]

x =\frac{4}{3}inch is the size in wheels on the scale model .

<u>Step-by-step explanation:</u>

Correct Question : Tom has a scale model of his car. The scale factor is 1 : 12. If the actual car has 16-inch wheels, what size are the wheels on the scale model?

We have , The scale factor is 1 : 12. We need to find If the actual car has 16-inch wheels, what size are the wheels on the scale model .Let's find out:

Ratio of size of wheels to actual size of wheels is 1:12 , but actual car has 16-inch wheels So ,

⇒ \frac{1}{12}  = \frac{x}{16}                 { x is size of wheel in scale model }

⇒ \frac{1(16)}{12}  = \frac{x}{16}(16)

⇒ x =\frac{16}{12}

⇒ x =\frac{4}{3}inch

Therefore , x =\frac{4}{3}inch is the size in wheels on the scale model .

5 0
4 years ago
A cargo grain leaves Chicago at noon travelling west at 120 km/h. At 2 pm, a passenger train leaves Chicago travelling east at 3
AfilCa [17]

Answer:

a) The trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.

b) At that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

Step-by-step explanation:

a) First, we need to find the distance traveled by the cargo train in the two hours before the passenger train leaves Chicago:

x_{1} = v_{1}t_{1} = 120 km/h*2h = 240 km                    

Now, we can find the time when the trains will be 1520 km apart:

1520 km = (x_{1} + 240 km) + x_{2}      

Where 1 is for the cargo train and 2 is for the passenger train.

1520 km = (v_{1}*t_{1} + 240 km) + v_{2}t_{2}      

Since we need to calculate the time when the trains are 1520 km apart, t₁ = t₂, so:

1520 km = (v_{1}*t + 240 km) + v_{2}t              

t = \frac{1520 km - 240 km}{120 km/h + 360 km/h} = 2.667h

For the cargo train, it will be 1520 km apart from the passenger train at:

t_{1} = 12 pm + 2 h + 40 min = 2:40 pm

And for a passenger train, it will be 1520 km apart from the cargo train at:

t_{2} = 2 pm + 2 h + 40 min = 4:40 pm  

Hence, the trains will be 1520 km apart at 2:40 pm for the cargo train and at 4:40 pm for the passenger train.  

b) The distance traveled by both trains is given by:

x_{1} = v_{1}*t + 240 km = 120 km/h*2.667 h + 240 km = 560.04 km    

x_{2} = v_{2}*t = 360 km/h*2.667 h = 960.12 km    

Therefore, at that time the cargo train has traveled 560.04 km and the passenger train has traveled 960.12 km.

I hope it helps you!        

5 0
3 years ago
State 2 possible solution points for the inequality. Use the form (x,y) for both points. *
Aleksandr [31]
Solution set of inequality-7<3x+2<11, where x is a real number
4 0
3 years ago
Does anyone know the answer?
meriva

Answer:

2/6

Step-by-step explanation:

there is only two fives with two dice, the dice only have six sides therefore the chances would be two out of five

6 0
3 years ago
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