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faust18 [17]
3 years ago
10

Divide z by 11. Then, add 8.

Mathematics
1 answer:
yulyashka [42]3 years ago
8 0
This may be the answer,hope it helps

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Customers can pick their own pumpkins at the great pumpkin patch. They pay 4$ to enter the patch and 3$ per pound for the pumpki
klasskru [66]

Given, Customers pay $4 to enter the pumpkin patch.

And also given, customers pay $3 per pound for the pumpkins.

Given, $y be the total cost and there are x pounds of pumpkins.

The cost for pumpkin per pound = $3.

Therefore, the cost for x pound pumpkins = $(3x)

As the total cost includes the payment for entering the patch also,

So the total cost y = 3x + 4

We have got the required equation.

The equation to model the total cost is y = 3x+4.

5 0
3 years ago
What are the coordinates of R’, the image of R(-4,3) after a reflection in the line y=x?
navik [9.2K]

Answer:

R'(3,-4)

Step-by-step explanation:

we know that

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places

so

The rule of the reflection across the line y=x is equal to

(x,y) ------> (y,x)

we have

R(-4,3) ------> R'(3,-4)

6 0
3 years ago
G(n)=80×(3/4)^n<br>Complete the recursive of g(n)​
PtichkaEL [24]
You could use photomath for thiss!
5 0
3 years ago
Use the​ F-scale measurements of tornadoes listed in the accompanying table. The range of the data is 4.0. Use the range rule of
Tcecarenko [31]

Answer:

Within 0.5 of ;

is not ;

Step-by-step explanation:

Given the data:

The actual standard deviation, = 1

;

The range rule of thumb to estimate the value if standard deviation is ;

Estimated standard deviation = Range / 4

The range = (maximum - minimum) values

The estimated standard deviation = 4 / 4 = 1

Hence, the estimated standard deviation is with 0.5 of the actual standard deviation, Thus, the estimated standard deviation is not substantially different from the actual standard deviation.

4 0
3 years ago
Simplify the algebraic expression 9+4(3c-1)
Natasha2012 [34]
9+4(3c-1)
13(3c-1)
39c-13

5 0
3 years ago
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