The range is the output of the function, and there are many ways to find it and write it. Let's find it first by plugging in all the domain values (domain means input) into the function:



We have all of our values. We can either write the range as:
{

}
or, subtract the smallest value from the largest one:

So, there are those ways to write it, there are more, but I think you should stick with the first way because that's how the problem was presented to you. If you have any questions, hmu!
???444489485857586868........................
Answer:
3y= -42
y= -14
Step-by-step explanation:
3y= -42
-42/3= -14
y= -14
Answer:
800%
Step-by-step explanation:
<h2><u>Percentage increase</u></h2><h3><u>formula:</u></h3>
change/ original * 100
change is 1.35 - 0.15 = 1.2
original is the amount in the beginning which is 0.15
= 1.2/0.15 * 100
=800 %
<em><u>the percentage increase is by 800%</u></em>
Answer:
Time(t) = 11.61 hours (Rounded to two decimal place)
Step-by-step explanation:
Given: The antibiotic clarithromycin is eliminated from the body according to the formula:
......[1]
where;
A - Amount remaining in the body(in milligram)
t - time in hours after the drug reaches peak concentration.
Given: Amount of drug in the body is reduced to 100 milligrams.
then,
Substitute the value of A = 100 milligrams in [1] we get;

Divide both sides by 500 we get;

Simplify:

Taking logarithm both sides with base e, then we have;

[ Using
]
or

[using value of
]
then;

Simplify:
t ≈11.61 hours.
Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams