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pantera1 [17]
3 years ago
12

Julio works at an electronics store where he earns $11 an hour. Last week, he received a $120 bonus. How many hours did he work

if he earned $505 total last week?
Mathematics
2 answers:
Whitepunk [10]3 years ago
6 0
Julio worked 35 hours
Sidana [21]3 years ago
4 0
julio worked 35 hours last week
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I need help seeing what I did wrong
Makovka662 [10]

Answer:  The two roots are x = 3/2 and x = -2

=========================================================

Explanation:

You have the right idea so far. But the two numbers should be 3 and -4 since

  • 3*(-4) = -12
  • 3+(-4) = -1

The -1 being the coefficient of the x term.

This means you need to change the -3x and 4x to 3x and -4x respectively. The other inner boxes are correct.

---------

Refer to the diagram below to see one way to fill out the box method, and that helps determine the factorization.

If we place a 2x to the left of -2x^2, then we need an -x up top because 2x*(-x) = -2x^2

Then based on that outer 2x, we need a -2 up top over the -4x. That way we get 2x*(-2) = -4x

So we have the factor -x-2 along the top

The last thing missing is the -3 to the left of 3x. Note how -3*(-x) = 3x in the left corner and -3*(-2) = 6 in the lower right corner.

We have the factor 2x-3 along the left side.

---------

The two factors are (2x-3) and (-x-2) which leads to the factorization (x+3)(-x+2)

The last thing to do is set each factor equal to 0 and solve for x

  • 2x-3 = 0 solves to x = 3/2 = 1.5
  • -x-2 = 0 solves to x = -2

The two roots are x = 3/2 and x = -2

8 0
3 years ago
Pllllllzzzzzzzzz help me
Fed [463]

Answer:

for the first one he will get $51

the second one is £2.70

Step-by-step explanation:

8 0
3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
2 years ago
Which statements about the cone are true? Check all
Tatiana [17]

Answer:

the radius is 9mm.

the base is calculated using the radius.

the volume is one-third the volume of a cylinder with the same height and diameter.

the volume of the cone is 297 mm'.

Step-by-step explanation:

i just took the quiz.

5 0
3 years ago
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What is 40% of 32?????????/
wel
The answer for ure question is 12.8
4 0
3 years ago
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