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3 years ago

12

Julio works at an electronics store where he earns $11 an hour. Last week, he received a $120 bonus. How many hours did he work

if he earned $505 total last week?

2 answers:

Whitepunk [10]3 years ago

6 0

Julio worked 35 hours

Sidana [21]3 years ago

4 0

julio worked 35 hours last week

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Multiply all of the numbers with each other and then simplify

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What is the equation of a line that is perpendicular to y = 3 x − 2 and passes through the point ( 6 , 8 )

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The slope of the given line is 3. Therefore, the slope of any line perpendicular to y = 3x - 2 is the negative reciprocal of 3, which is m = -1/3.

Starting with the point-slope equation of a straight line, obtain the specific equation applicable here by substituting the givens: m = -1/3, h = 6 and k = 8):

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A woman is emptying her aquarium at a steady rate with a small pump. The water pumped to a 12-in.-diameter cylindrical bucket, a

Temka [501]

Answer:

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

Step-by-step explanation:

Given that,

The diameter of cylindrical bucket = 12 in.

Depth is increasing at the rate of = 4.0 in per minutes.

i.e $\frac{dh_1}{dt}=4$

$h_1$ is depth of the bucket.

The volume of the bucket is V = $\pi r^2 h$

$=\pi \times 6^2\itimes h_1$

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Differentiating with respect yo t,

$\frac{dV}{dt}=36\pi \frac{dh_1}{dt}$

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$\therefore\frac{dV}{dt}=36\pi\times 4$

The rate of volume change of the bucket = The rate of volume change of the aquarium .

Given that,The aquarium measures 24 in × 36 in × 18 in.

When the water pumped out from the aquarium, the depth of the aquarium only changed.

Consider h be height of the aquarium.

The volume of the aquarium is V= ( 24× 36 ×h)

V= 24× 36 ×h

Differentiating with respect to t

$\frac{dV}{dt}=24\times 36 \times \frac{dh}{dt}$

Putting $\frac{dV}{dt}=36\pi\times 4$

$36\pi\times 4= 24\times 36\times \frac{dh}{dt}$

$\Rightarrow \frac{dh}{dt}=\frac{36\pi \times 4}{24\times 36}$

$\Rightarrow \frac{dh}{dt}=\frac{11}{21}$

Therefore the rate at which water level is dropping is $\frac{11}{21}$ in per minute.

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Anything to the power of 0 = 1

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