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fomenos
3 years ago
6

What is the median of 1,2,3,4,6

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0

Answer:

Step-by-step explanation:

3

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Julio is paid 1.4 times his normal hourly rate for each hour he works over 32 hours in a week. Last week he worked 43 hours and
nekit [7.7K]

Answer:

r = \$14.71

Step-by-step explanation:

Given

Normal Hour = 32 hours

Overtime = Hours above 32

Rate for Overtime = 1.4 times normal rate

Earnings = $535.62

Required

Determine the normal hour pay

First, we need to determine the hours worked overtime.

This is:

Overtime = 43 - 32

Overtime = 11

The equation that binds all the parameters is:

Earnings = Normal\ Hour * Normal\ Rate + Overtime * Overtime\ Rate

This gives:

535.62 = 21 * r + 11 * 1.4r

535.62 = 21r + 15.4r

535.62 = 36.4r

Solve for r

r = 535.62/36.4

r = \$14.71

4 0
3 years ago
a map has a scale of 1 : 50000. Bridgetown is 16.7km away from Littleton. What is the distance between these towns on the map?
lisov135 [29]

Answer:

if it is 1 cm answer is 3340cm

Step-by-step explanation:

1m = 100 cm

500m = 50000cm

change 16 .7 to m

16700

divide

16700/500

33.4

change to cm = 3340

3 0
4 years ago
Simplify the equation (-5-c) (-1) <br><br> a.) 5-c<br> b.) 5+c<br> c.) -5-c <br> d.) -5+c
Nimfa-mama [501]

-1(-5-c)

-1*-5=5

-1*-c=c

:5+c

7 0
3 years ago
Read 2 more answers
The highest temperature recorded in June in San Antonio was 109°F. The lowest temperature was 64°F. Which integer best represent
Dominik [7]
64 degrease farinheight
8 0
3 years ago
True or False (&amp; Justify): If a ball is thrown horizontally from the top edge of a 150m building at a speed of 25 m/sec, the
kap26 [50]

Answer:

38.6 m/s

Step-by-step explanation:

The motion of the ball is a projectile motion, which consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

Therefore we have to analyze the horizontal and vertical motion separately.

Along the horizontal direction, the velocity is constant during the motion, since there are no forces acting in this direction. So the horizontal velocity 3 seconds after the launch will be the same as the velocity at the launch:

v_x = v_0 = 25 m/s

The vertical velocity instead changes according to the suvat equation:

v_y = u_y - gt

where

u_y=0 is the initial vertical velocity

g=9.8 m/s^2 is the acceleration due to gravity

t is the time

Therefore, after t = 3 s,

v_y=0-(9.8)(3)=-29.4 m/s

So the velocity after 3 seconds is < 25, -29.4 > m/s. The magnitude of the velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{25^2+(-29.4)^2}=38.6 m/s

3 0
3 years ago
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