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3 years ago

The following table shows the times of trains between Juno and Odiham.

Mathematics

1 answer:

Luba_88 [7]3 years ago

8 0

Answer:

(a) The earliest time that Ferdo can be back at Juno station is 12:15

Step-by-step explanation:

From the given table, we have;

The starting time for train departure from Juno = 07:15

The frequency of train departures from Juno = Every 20 minutes

The time of departure, 't₁' of first train that departs from Juno after 08:30 is given as follows;

The train departure times from Juno = 07:15, 07:35, 07:55, 08:15, 08:35

Therefore;

The time at which the first train departs from Juno after 08:30 = 08:35

The time it takes a train to travel from Juno to Odiham = 0:805 - 07:15 = 50 minutes

The time of arrival of the train Ferdo takes from Juno at Odiham = 08:35 + 50 minutes = 09:25

The number of hours Ferdo spends at Odiham = 2 hours

The time after which Ferdo departs from Odiham = 09:25 + 02:00 = 11:25

The time of departure of the train from Odiham after 11:25 = 08:05 + 20 minutes × 10

Therefore, the time of departure of the train from Odiham after = 11:25

The time it takes on the trip back to Juno from Odiham = 50 minutes

The earliest time that Ferdo can be back at Juno station = 11:25 + 50 minutes = 12:15

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A lot of math is about matching patterns.

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Comment on the graph

I find it useful to see a picture with these things. In the attached graphing calculator output, the blue curve is left 6 and up 4 from the red curve. The blue curve is g(x); the red one is f(x).