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3 years ago

7

In circle X, if m∠QST = 71°, and mRS⌢ = 46°, find each measure. You will not use all of the answers.

1 answer:

lana66690 [7]3 years ago

8 0

Answer:

142,180 and 10 and 23 and that it

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x

Andrei [34K]

Answer:

$\large\boxed{A.\ (x+6)^2+(y+10)^2=20}$

Step-by-step explanation:

The standard form of an equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10$

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute (-6, -10) and (-8, -6):

$r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}$

Finally we have

$(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20$

5 0

3 years ago

Read 2 more answers

Prove that 3:8 is equivalent to 12:32.

ANEK [815]

3:8 can also be written as 3/8

<span>12:32 can also be written as 12/32

</span> $\frac{12}{32} = \frac{3\times 4}{8\times 4} = \frac{3}{8}$

<span>So thus 3:8 is equivalent to 12:32</span>

7 0

3 years ago

Use special right triangle properties to solve for the missing sides.

stiv31 [10]

Answer:

cos30=12/x

√3/2=12/x

x=12×2/√3=24√3/3=8√3

sin30=y/x

1/2=y/8√3

1/2×8√3=y

y=4√3

5 0

3 years ago

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1, show that their volumes are in

Nuetrik [128]

<h2> $\large\bold{\underline{\underline{Question:-}}}$ </h2>

Two cones have their heights in the ratio 1 : 3 and the radius of their bases in the ratio 3 : 1 show that their volumes are in the ratio 3 : 1.

<h2> $\large\bold{\underline{\underline{Solution:-}}}$ </h2>

⇒ Ratio of heights of two cones = 1 : 3

⇒ Ratio of radius of their bases = 3 : 1

⇒ We know that V = 1/3πr²h

⇒ Ratio of their volume = V1 : V2

$\underline{ \underline{ \sf{Let's \: find \: the \: ratio \: of \: their \: volumes:}}}$

${ \implies{ \sf {V _{1} : V_{2}}}}$

${ \implies{ \sf{ \frac{1}{3} \pi \: { r_{1}}^{2} h_{1} : \frac{1}{3} \pi \: { r_{2} }^{2} h_{2}}}}$

${ \implies{ \sf{ {r_{1}}^{2} h_{1} : { r_{2}}^{2} h_{2}}}}$

${ \implies{ \sf{ \frac{ { r_{1} }^{2} }{ { r_{2} }^{2} } : \frac{ h_{2} }{ h_{1} } }}} \\$

${ \implies{ \sf{ \frac{ {3}^{2} }{ {1}^{2} } : \frac{3}{1} }}} \\$

${ \implies{ \sf{ \frac{9}{1} : \frac{3}{1} }}} \\$

${ \implies{ \sf{3 : 1}}} \\$

${ \therefore{ \sf{ \green{Ratio \: of \: their \: volumes = 3 : 1}}}}$

4 0

3 years ago

Y + 4 = 1 . 5 ( x − 4 ) how do you solve this linear equation for standard form in algebra

Lena [83]

Standard form is ax+by=c
Steps:
y + 4 = 1.5(x - 4)
y + 4 = 1.5x - 6
-1.5x + y = -10 is the standard form.

6 0

3 years ago