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andreyandreev [35.5K]

3 years ago

7

Cherise is tracking her heart rate during a 20-mile bike ride. In 1/3 min, her heart beats 56 times. What is Cherise’s heart rat

e and intensity level?

2 answers:

Pavel [41]3 years ago

4 0

The intensity level is hard and for the first part, it’s 168. and something. Sorry that’s all I figured out I’m not too smart :/

IceJOKER [234]3 years ago

3 0

Answer:

<u>168 </u>bmp, the level intensity is<u> HARD</u>

Step-by-step explanation:

I got this correct, Get that A+

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. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST <u>we first need to find the gradient of ST, using the gradient formula.</u>

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$

and the line should pass throught S as well, i.e $(5,-4)$ . Plugging all these values in the equation we'll get.

$(y - (-4)) = \dfrac{13}{16}(x-5)$

$y +4 = \dfrac{13x}{16}-\dfrac{65}{16}$

$y = \dfrac{13x}{16}-\dfrac{65}{16}-4$

$y=\dfrac{13x}{16}-\dfrac{129}{16}$

this is the equation of the line that is perpendicular to ST and passes through S

a) Line through T and Perpendicular to ST

we'll do the same thing for $T(-8,12)$

$(y - y_1) = m(x-x_1)$

$(y -12) = \dfrac{13}{16}(x+8)$

$y = \dfrac{13x}{16}+ \dfrac{104}{16}+12$

$y = \dfrac{13x}{16}+ \dfrac{37}{2}$

this is the equation of the line that is perpendicular to ST and passes through T

7 0

3 years ago

I’m not sure with this question help!

labwork [276]

Answer: C.) 3 to the power of negative two, 1.3 x 10 to the power of negative one, 1/3, and 3 squared.

Step-by-step explanation:

3 to the power of negative 2 = 0.11111111111

3 squared is 1.73205080757

1.3 x 10 to the power of negative 1 = 0.13

1/3 converted to a decimal is 0.333

Now that we know what everything equals we know that anything that doesn't start with 3 squared is right and a little cheat is that only one of them start with 1/3 so we know that the second biggest is 1/3 so it is C.) 3 to the power of negative two, 1.3 x 10 to the power of negative one, 1/3, and 3 squared.

7 0

3 years ago

Read 2 more answers

Plss help me solve these 2 !!!!!!!!!!! for a brainlist ;))

lisabon 2012 [21]

Answer:

1. d

2. a

Step-by-step explanation:

Thats how it goes!

Branliest plzzz

3 0

3 years ago

Three times the difference of ten and a number is four.

Paul [167]

Answer:

3 (10-a) = 4 i think

Step-by-step explanation:

7 0

3 years ago

What is the diameter of a human hair written in scientific notation?<br> Plz explain! Thanks! :D

Anestetic [448]

The diameter of human hair is 8.0 x 10^-6
hope this helps :)

4 0

3 years ago