![\displaystyle\lim_{n\to\infty}\sqrt[n]{\left|\left(\frac{5n+15}{2n-1}\right)^n\right|}=\lim_{n\to\infty}\frac{5n+15}{2n-1}=\dfrac52](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Clim_%7Bn%5Cto%5Cinfty%7D%5Csqrt%5Bn%5D%7B%5Cleft%7C%5Cleft%28%5Cfrac%7B5n%2B15%7D%7B2n-1%7D%5Cright%29%5En%5Cright%7C%7D%3D%5Clim_%7Bn%5Cto%5Cinfty%7D%5Cfrac%7B5n%2B15%7D%7B2n-1%7D%3D%5Cdfrac52)
Since this limit exceeds 1, the series diverges.
(-8 + 0 / 2) (7 + 1 / 2)
(-8/2) (8/2)
(-4) (4)
Midpoint = (-4,4) [Answer]
Answer:
3040
Step-by-step explanation:
given arithmetic progression is
70,100,130,...
here
first term (a)=70
common difference (d)=100-70=30
number of term n=100
using the formula of arithmetic progression
an=a+(n-1)d
a100=70+(100-1)30
a100=70+99×30
a100=70+2970
a100=3040
ANSWER
The vertical asymptotes are

<u>EXPLANATION</u>
We have

For vertical asymptotes we set the denominator to zero and solve the quadratic equation;


We split the middle term to obtain,




Therefore the vertical asymptotes are

Answer:
The equation of the line is y = (-1/2)x + 5
Step-by-step explanation:

First of all, have to find gradient using the formula above :
(2,4) & (14,-2)
m = (-2-4) / (14-2)
= -6 / 12
= -1/2
Second, using y = mx + b as b is a constant and is a y-intercept. Using any of these 2 coordinates to find the value of b with given gradient :
y = mx + b
Let y=4 & x=2
4 = (-1/2)(2) + b
b = 4 + 1
= 5
Lastly, put the value of gradient and y-intercept into the equation :
y = mx + b
Let m=-1/2 & b=5
y = (-1/2)x + 5