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Artemon [7]
3 years ago
7

Can someone plz help me with this one problem plz!!!! (I Will Mark Brainliest)!!!!!

Mathematics
1 answer:
Vinil7 [7]3 years ago
6 0

Answer:

it would be in the middle? like starting at 0

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Consider the function f(x)=2|x|-3. What is f(-3)?
olganol [36]

f(-3)=2|-3|-3=6-3=3\\f(-3)=3

Hope I helped and have a great day!

P.S. brainliest would really help im one away from virtuoso

8 0
3 years ago
Evaluate |x + y|, for x = 8 and y = -15.<br><br> 7<br> -7<br> 23<br> -23
natka813 [3]

Answer:

7

Step-by-step explanation:

When evaluating absolute values, a great way to remember what they do is simple. No matter the number, whether it is negative or positive, the number(s) IN THE absolute values are ALWAYS positive.

So, |x + y| is then substituted with the numbers given for the variables.

|x + y|

|8 - 15|

|-7|

7

Hope this helps!

3 0
3 years ago
PLEASE HELP GUYS i am struggling so much, two questions
ankoles [38]

Answer: the equation of the standard parabola

1) (y-6)^2 = 4 (x-1)

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

<u>Explanation </u>

<u>Parabola:-</u>

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

  • The locus of P such that \frac{SP}{PM} = constant
  • The fixed point  'S' is called the Focus.
  • The fixed line'l 'is called the directrix of the conic
  • The constant ratio is known as the eccentricity, denoted by 'e'
  • If e=1 , the conic is called a parabola

1) <u> Step 1</u> :-

Given the focus   S = (2,6) and directrix is x=0

we know that \frac{SP}{PM}=1

now cross multiplication , we get

SP = PM

squaring on both sides,we get

SP^{2} = PM^2

step 2:-

now using distance formula is

  • \sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)

Given S =(2,6) and P(x,y) be any point on parabola

SP^2 = (x-2)^2+(y-6)^2........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

  • \frac{ax_{1}+by_{1}+c   }{\sqrt{a^2+b^2} }

Given the directrix is x =0 and P(x,y) be any point on parabola

PM^2 = \frac{x^2}{\sqrt{1}^2 }......(2)

equating equation(1) and equation (2), on simplification

we get (x-2)^2+(y-6)^2 = x^2.....(3)

  • apply (a-b)^2 = a^2+  b^2+2 ab

now the equation (3) is

(y-6)^2 = 4 x-4

now the standard form of parabola is

(y-k)^2 = 4 a(x-h)

<u>Final answer</u>:-

(y-6)^2 = 4 (x-1)

2) <u> Explanation:-</u>

<u>step 1:</u>

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

  • Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

(x-h)^2 = 4 a (y-k)

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of AS = \sqrt{(-5-(-5)^2+(2-6)^2}

 on simplification we get a =4

<u>Final answe</u>r :-

the vertex (h,k) = (-5,2) and a=4

(x-h)^2 = 4 a (y-k)

The standard parabola is (x+5)^2 = 16 (y-2)

5 0
3 years ago
. Which expression has a value of 6? *
Anarel [89]

Answer:

(6÷3) * 4 + 8 is the equation with the value of 6

3 0
3 years ago
Consider the two savings plans below. Compare the balances in each year after 14 years. Which person deposited more money in the
zhuklara [117]

The balance in Yolanda's saving plan after 14 years is; $9,455.36

<h3>How to calculate future value?</h3>

We want to find the balance in Yolanda's saving plan after 14 years.

For Yolanda;

PV = 0

PMT = 250

i% = 4%/12 = 0.33%

N = 14 yrs * 12 = 168

FV = ?

For Zach:

PV = 0

PMT = $3300

i% = 4%

N = 14 yrs

FV = ?

From online future value calculator, we have;

Yolanda FV = $9,455.36

Zach FV = $47,204.19

Read more about Future Value at; brainly.com/question/24703884

#SPJ1

3 0
2 years ago
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