Solve the quadratic equations by completing the square. x^2-4x=-1
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Answer:
The statements are incorrect as: The sum of even numbers from 1 to 100(i.e. 2550) is not double\twice of the sum of odd numbers from 1 to 100(i.e. 2500).
Step-by-step explanation:
We know that sum of an Arithmetic Progression(A.P.) is given by:
where 'n' denotes the "number" of digits whose sum is to be determined, 'a' denotes the first digit of the series and '' denote last digit of the series.
Now the sum of even numbers i.e. 2+4+6+8+....+100 is given by the use of sum of the arithmetic progression since the series is an A.P. with a common difference of 2.
image with explanation
Hence, sum of even numbers from 1 to 100 is 2550.
Also the series of odd numbers is an A.P. with a common difference of 2.
sum of odd numbers from 1 to 100 is given by: 1+3+5+....+99
.
Hence, the sum of all the odd numbers from 1 to 100 is 2500.
Clearly the sum of even numbers from 1 to 100(i.e. 2550) is not double of the sum of odd numbers from 1 to 100(i.e. 2500).
Hence the statement is incorrect.
Step-by-step explanation:
The probability that all three players obtain an odd sum is 3/14.
<h3>What is probability?</h3>The probability is the ratio of possible distributions to the total distributions.
I.e.,
Probability = (possible distributions)/(total distributions)
<h3>Calculation:</h3>Given that,
There are nine tiles - 1, 2, 3,...9, respectively.
A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.
In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.
The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.
So,
One player can be selected in ways.
The 3 odd tiles out of 5 can be selected in ways.
The remaining 2 odd tiles can be selected and distributed in ways.
The remaining 4 even tiles can be equally distributed in ways.
So, the possible distributions = ×
×
×
⇒ 3 × 10 × 2 × 6 = 360
To find the total distributions,
The first player needs 3 tiles from the 9 tiles in ways
The second player needs 3 tiles from the remaining 6 tiles in ways
The third player takes the remaining tiles in 1 way.
So, the total distributions = 84 × 20 × 1 = 1680
Therefore, the required probability = (possible distributions)/(total distributions)
⇒ Probability = 360/1680 = 3/14.
So, the required probability for the three players to obtain an odd sum is 3/14.
Learn more about the probability of distributions here:
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Let
x------> the number of multiple choice question
y------> the number of free response question
we know that
-----> equation A
-----> equation B
Substitute equation B in equation A
Find the value of x
therefore
<u>the answer is</u>
the number of multiple choice question are
the number of free response question are