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katovenus [111]
3 years ago
7

HELP PLZ BRAINLIEST i will give

Mathematics
1 answer:
Artist 52 [7]3 years ago
6 0

Answer:

-3/2

Step-by-step explanation:

Find two points on the graph: (-1,2) and (1,-1).

Start at point (-1,2) and go down until you are at the same "x-line" as the point (1,-1). You should count 3 squares. Now, count squares to the right until you reach the point (1,-1). You should count 2. So, you have 3/2. However, the line starts from the top of the left side of the graph, so the slope is negative.

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Which Graph Represents The solution set of this inequality?
Alex

Answer:

B

Step-by-step explanation:

1. In order to determine the inequality, you must first solve the solution set to determine what x is less than.

So you would do this:

1 + 2x < 9             Subtract 1

2x < 8                  Divide by 2

x < 4

2. Next, you need to understand the difference between an open circle and a closed circle shown on the solution sets.

An open circle is equal to the following inequalities:

<, >

A Closed circle represents inequalities in situations such as:

greater than or equal to, or less than or equal to

3. Because the inequality above represents only less than or greater than the inequality sets should have an open circle being used.

Since x is less than 4 it should be moving to the left of the line inequality set.

5 0
3 years ago
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Westkost [7]

Answer:

4:1

Step-by-step explanation:

4 trucks for 1 van

3 0
2 years ago
Someone plz help me. There are 2 answer choices
givi [52]

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3 0
3 years ago
Read 2 more answers
Conner has collected 29 out of the 50 state flags. What percentage of the state flags has Conner collected.
Yakvenalex [24]

Answer:

58%

Step-by-step explanation:

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What is the best result for h?
Kryger [21]

Answer: First option.

Step-by-step explanation:

To solve for "h" from the given the equation S=2\pi rh+2\pi r^2, you need to:

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Then you need to apply the Division property of equality and divide both sides of the equation by 2\pi r.

Then:

S-2\pi r^2=2\pi rh+2\pi r^2-2\pi r^2\\\\S-2\pi r^2=2\pi rh\\\\\frac{S}{2\pi r}-\frac{2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r}\\\\\frac{S}{2\pi r}-r=h

6 0
3 years ago
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