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3 years ago

Please add a picture explaining how to do this! Ty!!

Mathematics

1 answer:

laila [671]3 years ago

3 0

HAHAHA FINALLY lol, this is easyyy

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Find the area of this parallelogram<br>8cm<br>10cm<br>14cm

Natasha2012 [34]

Answer:

112 $cm^{2}$

Step-by-step explanation:

A=bh

A=14*8

A=112

8 0

3 years ago

180 euros to the uk exchange rate was €1.2 to £1 how much did he get in £ sterling

Nataliya [291]

Here you can use proportion:

The ratio betwen €1.2 to £1

is the same as the ratio between €180 to £x

Mathematically this means that

$\dfrac{1.2}{180} =\dfrac{1}{x}$ .

Now

$1.2\cdot x=180\cdot 1\\\\ x=\dfrac{180}{1.2} \\ \\x=150$

Answer: €180 is £150

6 0

4 years ago

Read 2 more answers

Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

Ostrovityanka [42]

Answer:

2.25

Step-by-step explanation:

The computation of the number c that satisfied is shown below:

Given that

$f(x) = \sqrt{x}$

Interval = (0,9)

According to the Rolle's mean value theorem,

If f(x) is continuous in {a,b) and it is distinct also

And, f(a) ≠ f(b) so its existance should be at least one value

i.e

$f^i(c) = \frac{f(b) - f(a)}{b -a }$

After this,

$f(x) = \sqrt{x} \\\\ f^i(x) = \frac{1}{2}x ^{\frac{1}{2} - 1} \\\\ = \frac{1}{2}x ^{\frac{-1}{2}$

$f^i(x) = \frac{1}{{2}\sqrt{x} } = f^i(c) = \frac{1}{{2}\sqrt{c} } \\\\\a = 0, f (a) = f(o) = \sqrt{0} = 0 \\\\\ b = 9 , f (b) = f(a) = \sqrt{9} = 3\\$

After this,

Put the values of a and b to the above equation

$f^i(c) = \frac{f(b) - f(a)}{b - a} \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}$