Let S = his average speed.
Let D = distance traveled one way
Time = distance / speed
Set up an equation:
d/6 + d/12 = 2d/S
Multiply the equation by 12s:
12s(d/6) + 12s(d/12) = 12s(2d/s)
Simplify to get:
2sd + sd = 24d
Combine like terms:
3sd = 24d
Divide both sides by d:
3s = 24
Divide both sides by 3:
s = 24/3
s = 8
His average speed was 8 mph.
Answer:
-10x² - 7x + 7
Step-by-step explanation:
Subtract:
- -5x² - 8x - 1 - (5x² - x - 8)
- -5x² - 5x² - 8x + x - 1 + 8
- -10x² - 7x + 7
Remember: subtracting a negative number is adding that number
-Chetan K
(y - yo) = m.(x - xo)
We have the points (4, 12) and (x, 18) with slope of 3.
(18 - 12) = 3.(x - 4)
6 = 3x - 12
3x = 6 + 12
3x = 18
x = 18/3
x = 6
The simple answer to your question is -36b-27
Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
