I think these are the correct answers
45. 13/36
46. 86/63
47. 19/42
48. 17/30
Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
please mark me the brainiest
Answer:
B:31.5
Step-by-step explanation:
Find areas of both rectangles by multiplying the 2 given values (12 & 15)
Take the sides parallel to the triangles non-hypotenuse sides (3 & 3)
Take both values and add them over 2
Receive the answer 4.5
Add that to the rectangle values for an answer of 31.5
Hope this helps
Have a good day
Answer:
(q)




(r)





(s)





Step-by-step explanation:
Answer:
d
Step-by-step explanation:
Hope this helps! Good luck!