(1 point) Consider the universal set U={1,2,3,4,5,6,7,8,9,10}, define the set A be the even numbers, the set B be the odd number
Sloan [31]
Answer:
a) AUC = {2,4,6,8,10}
b) BnC = {}
c) AnB = {}
d) B-C = B = {1,3,5,7,9}
Step-by-step explanation:
The set A is the even numbers, those that are divisible by two.
So A = {2,4,6,8,10}
B is the odd numbe.rs. An odd number is a number that is not divisible by two.
So B = {1,3,5,7,9}.
C = {4,5,6}, as the problem states
a) The union of sets is a set containing all elements that are in at least one of the sets. So the union of A and C is a set that contains all elements that are in at least one of A or C.
So AUC = {2,4,6,8,10}.
b) The intersection of two sets consists of all elements that in both sets. So, the intersection of B and C is the set that contains all elements that are in both B and C.
There are no elements that are in both B and C, so the intersection is an empty set
BnC = {}
c) Same explanation as b), there are no elements that are in both A and B, so another empty set.
AnB = {}
d) The difference of sets B and C consists of all elements that are in B and not in C. We already have in b) that BnC = {}, so:
B-C = B = {1,3,5,7,9}
Answer:
<em>D. Obtuse</em>
Step-by-step explanation:
Answer:
For this case the population is described as:
All the college students
And the political have a list of 3456 undergraduates at her college for the sampling frame.
The sample would be the 104 students who return the survey.
Is important to notice that since he know the information about her college she can apply inference about the parameter of interest just at her college and not about all the possible students of college.
Step-by-step explanation:
For this case the population is described as:
All the college students
And the political have a list of 3456 undergraduates at her college for the sampling frame.
The sample would be the 104 students who return the survey.
Is important to notice that since he know the information about her college she can apply inference about the parameter of interest just at her college and not about all the possible students of college.
For this case we can also find the non reponse rate since we know that the total of questionnaires are 250 and she got back just 104 answered
So we have a non response rate of 58.4 %
do: first of first bracket x first of 2nd bracket
+( first of 1st bracket x 2nd of 2nd bracket)
+(2nd of 1st bracket x 1st of 2nd bracket)
+ (2nd of 1st bracket x 2nd of 2nd bracket)
== 10n -16n +20n+32= 14n+32
total marbles: 2+3+7 = 12
add blue and yellow 2+3=5
7 marbles aren't blue or yellow
probability = 7/12 marble is not one of those
