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aleksklad [387]
3 years ago
10

I will give Brainlyest What is true about a "point-to-multipoint" network configuration?

Computers and Technology
1 answer:
Bumek [7]3 years ago
7 0

Answer:

a

Explanation:

Beacause im smart and i trust my self my answer is corect

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Write a program that will predict the size of a population of organisms. The program should ask the user for the starting number
sineoko [7]

Answer:

// using c++ language

#include "stdafx.h";

#include <iostream>

#include<cmath>

using namespace std;

//start

int main()

{

 //Declaration of variables in the program

 double start_organisms;

 double daily_increase;

 int days;

 double updated_organisms;

 //The user enters the number of organisms as desired

 cout << "Enter the starting number of organisms: ";

 cin >> start_organisms;

 //Validating input data

 while (start_organisms < 2)

 {

     cout << "The starting number of organisms must be at least 2.\n";

     cout << "Enter the starting number of organisms: ";

     cin >> start_organisms;

 }

 //The user enters daily input, here's where we apply the 5.2% given in question

 cout << "Enter the daily population increase: ";

 cin>> daily_increase;

 //Validating the increase

 while (daily_increase < 0)

 {

     cout << "The average daily population increase must be a positive value.\n ";

     cout << "Enter the daily population increase: ";

     cin >> daily_increase;

 }

 //The user enters number of days

 cout << "Enter the number of days: ";

 cin >> days;

 //Validating the number of days

 while (days<1)

 {

     cout << "The number of days must be at least 1.\n";

     cout << "Enter the number of days: ";

     cin >> days;

 }

 

 //Final calculation and display of results based on formulas

 for (int i = 0; i < days; i++)

 {

     updated_organisms = start_organisms + (daily_increase*start_organisms);

     cout << "On day " << i + 1 << " the population size was " << round(updated_organisms)<<"."<<"\n";

     

     start_organisms = updated_organisms;

 }

 system("pause");

  return 0;

//end

}

Explanation:

6 0
3 years ago
What happens when the programmer tries to access an array cell whose index is greater than or equal to its logical size?
just olya [345]

Answer:

When a programmer tries to access an item in an array cell whose index is greater than or equal to the array's logical size, this data element or item is garbage. This means that currently, the item is not the part of the program's useful data. Garbage contains objects or data which will not be used by a program running on it. So the value returned could be either of the two:

  • Value would be an arbitrary or random number if it is an array of numbers. Arbitrary means that the value is not predefined or specified in advance.
  • Value returned would be null if it is an array of objects.

                                                           

 

3 0
3 years ago
Someone pls help me do this and don't ask for brainliest or say random answers not related to this.
Marat540 [252]
I used to use pixlr all the time so i should know.
Ok so

1 is picker
2 is lasso select
3 is crop
4 is Liquefy
5 is clone
6 is dodge/burn
7 is Pen
8 is Eraser
9 is Gradient
10 is Text
11 is Zoom
12 is Switch Colors
13 is Marquee Select
14 is Wand select
15 is Cutout/Mask
16 is Heal
17 is Blur/Sharpen
18 is Sponge Color
19 is draw
20 is Fill
21 is I don’t know I have never seen that before
22 is Picker

So sorry if it took a while i did not know what the star was
3 0
3 years ago
Read 2 more answers
(asking again because point-hogs exist)
yawa3891 [41]

The answer is 2-to-the-power-of-n, since for every input, the number of different combinations doubles. From your list I think answer A is meant to indicate 2ⁿ.

6 0
3 years ago
Assume that source elements of length k are mapped in some uniform fashion into a target elements of length p. If each digit can
lukranit [14]

Answer And explanation

a)

r^k has 1/r^k probability guess the correct source

b)

Each element in r^p  is mapped by r^k / r^p . There are r^k^-^p  So there are  r^k^-^p -1 elements.

number of target elements = r^k^-^p

number of source elements = r^k^-^p -1

probability = r^k^-^p -1 /r^k

c) Probability of the correct target element

1/r^p

6 0
3 years ago
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