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frozen [14]
3 years ago
5

Find the 12th term of the sequence: 48, 44, 40, 36... A.4 B.8 C.12 D.16 ​

Mathematics
2 answers:
Igoryamba3 years ago
5 0

Answer:

So the answer is 4

48,44,40,36,32,28,24,20,16,12,8,4

You can just do 4×12=48

Step-by-step explanation:

4 is being subtracted

gregori [183]3 years ago
4 0

Answer:

the answer that I found is A. 4

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The width can be x.
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If a dealer purchased a stove for 558.54, after a 46% trade discount, what is the dealers cost?
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3 years ago
Read 2 more answers
Please answer quickly, I need to get this done. I'll mark brainliest.
worty [1.4K]

J (-4, 1), K (-4, -2), L (-3, -1)

(a) To rotate a point 90° counterclockwise about the origin, multiply the y-coordinate by -1 and then interchange the z- and y- coordinates.

(x, y)'' = (-y, x)

Substitute all of J (-4, 1), K (-4, -2), L (-3, -1) for (x, y)

Solution:

J'' = J (-4, 1) × (x, -1) = (-4, -1)

K'' = K (-4, -2) × (x, -1) = (-4, 2)

L'' = L (-3, -1) × (x, -1) = (-3, 1)

J'' (-1, -4), K'' (2, -4), L'' (1, -3)

Image ▲J"K"L": Look at the first attached picture.

(b) To reflect a point in the y-axis, we multiply its x-coordinate by -1.

Substitute all of J (-4, 1), K (-4, -2), L (-3, -1) for (x, y)

Multiplying by -1:

J'' = J (-4, 1) × (-1, y) = (4, 1)

K'' = K (-4, -2) × (-1, y) = (4, -2)

L'' = L (-3, -1) × (-1, y) = (3, -1)

J'' (4, 1), K'' (4, -2), L'' (3, -1)

Image ▲J"K"L": Look at the second attached picture.



7 0
3 years ago
Quadrilateral ABCD has coordinates (3, 1), (4, 4), (7, 5), (6, 2). Quadrilateral ABCD is a
Sever21 [200]
I think it’s c let me double check just in case
8 0
4 years ago
Read 2 more answers
Help needed ASAP will give brainliest
Rom4ik [11]

Answer:

-5

Step-by-step explanation:

counting is like backwards in negatives so a +5 is slow and a +25 is high but in negatives its the opposite because you are missing that many

I dont really know who to explain it but I hope this helps

5 0
4 years ago
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