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frozen [14]
3 years ago
5

Find the 12th term of the sequence: 48, 44, 40, 36... A.4 B.8 C.12 D.16 ​

Mathematics
2 answers:
Igoryamba3 years ago
5 0

Answer:

So the answer is 4

48,44,40,36,32,28,24,20,16,12,8,4

You can just do 4×12=48

Step-by-step explanation:

4 is being subtracted

gregori [183]3 years ago
4 0

Answer:

the answer that I found is A. 4

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Find the value of x​
Ivahew [28]

Answer:

x=27

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

90 + x+23 + x+13 = 180

Combine like terms

126 +2x = 180

Subtract 126 from each side

126-126 +2x=180-126

2x =54

Divide by 2

2x/2 = 54/2

x = 27

4 0
3 years ago
Help pleaseeeeeee quickly
shusha [124]

The first sentence in the chart belongs to the subjunctive mood, while the other sentences can be classified as part of the conditional mood.

<h3>What is a verb mood?</h3>

In language, the verb mood indicates the attitude of the speaker, and therefore, it provides clues about the way language is used. For example, the imperative mode indicates an order is being given.

<h3>What is the difference between the conditional and the subjunctive mood?</h3>
  • Subjunctive: It is used for expressing wishes; due to this, it is common to find the use of words such as "wish".
  • Conditional: It expresses a condition or a situation that will/can happen if another situation occurs. This can be identified due to the use of "if".

Based on this, the first sentences belongs to the subjunctive mood, while the other sentences are part of the conditional.

Learn more about the subjunctive in: brainly.com/question/22728240

#SPJ1

6 0
2 years ago
Evaluate c (y + 7 sin(x)) dx + (z2 + 9 cos(y)) dy + x3 dz where c is the curve r(t) = sin(t), cos(t), sin(2t) , 0 ≤ t ≤ 2π. (hin
saw5 [17]
Treat \mathcal C as the boundary of the region \mathcal S, where \mathcal S is the part of the surface z=2xy bounded by \mathcal C. We write

\displaystyle\int_{\mathcal C}(y+7\sin x)\,\mathrm dx+(z^2+9\cos y)\,\mathrm dy+x^3\,\mathrm dz=\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r

with \mathbf f=(y+7\sin x,z^2+9\cos y,x^3).

By Stoke's theorem, the line integral is equivalent to the surface integral over \mathcal S of the curl of \mathbf f. We have


\nabla\times\mathbf f=(-2z,-3x^2,-1)

so the line integral is equivalent to

\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\mathrm d\mathbf S
=\displaystyle\iint_{\mathcal S}\nabla\times\mathbf f\cdot\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv


where \mathbf s(u,v) is a vector-valued function that parameterizes \mathcal S. In this case, we can take

\mathbf s(u,v)=(u\cos v,u\sin v,2u^2\cos v\sin v)=(u\cos v,u\sin v,u^2\sin2v)

with 0\le u\le1 and 0\le v\le2\pi. Then

\mathrm d\mathbf S=\left(\dfrac{\partial\mathbf s}{\partial u}\times\dfrac{\partial\mathbf s}{\partial v}\right)\,\mathrm du\,\mathrm dv=(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv

and the integral becomes

\displaystyle\iint_{\mathcal S}(-2u^2\sin2v,-3u^2\cos^2v,-1)\cdot(2u^2\cos v,2u^2\sin v,-u)\,\mathrm du\,\mathrm dv
=\displaystyle\int_{v=0}^{v=2\pi}\int_{u=0}^{u=1}u-6u^4\sin^3v-4u^4\cos v\sin2v\,\mathrm du\,\mathrm dv=\pi<span />
4 0
3 years ago
If today temperature is 7°C yesterday’s temperature was 13°C cooler what was the temperature yesterday
mel-nik [20]
Yessss yes uws uesbauaiiwns
3 0
3 years ago
Read 2 more answers
Margot purchases book tees from the warehouse and marks up those prices by 20% for retail sale when tease go on sold for more th
rusak2 [61]
No she's not correct,,,
If the teas are $50 to start with 20% up from $50 is $62.50
if she counts down 20% down from that it wouldn't be $50 but be $40.
So she would not break even.

6 0
3 years ago
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