Quadrilateral ABCD has coordinates (3, 1), (4, 4), (7, 5), (6, 2). Quadrilateral ABCD is a
2 answers:
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To find the zeros of this function, we must first set the entire function equal to 0
f(x) = x² - 2x - 15 = 0
Since this is a quadratic function, we must use the quadratic formula, which is:
Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15
Now let's plug those in:
which simplifies to:
Simplified further:
And divide it by the 2 on the bottom gives us:
2+4 = 6
2-4 = -2
So the zeros of this function are -2 and 6
f(x) = x² - 2x - 15 = 0
Since this is a quadratic function, we must use the quadratic formula, which is:
Let's assign a, b, and c using our first function
x² means a = 1 (because it could be written as 1x²)
-2x means b = -2
-15 means c = -15
Now let's plug those in:
which simplifies to:
Simplified further:
And divide it by the 2 on the bottom gives us:
2+4 = 6
2-4 = -2
So the zeros of this function are -2 and 6
Which polynomial is equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x)?
<h3><u><em>Answer:</em></u></h3>The polynomial equal to (-3x^2 + 2x - 3) subtracted from (x^3 - x^2 + 3x) is
Given that two polynomials are: and
We have to find the result when is subtracted from
In basic arithmetic operations,
when "a" is subtracted from "b" , the result is b - a
Similarly,
When is subtracted from
, the result is:
Let us solve the above expression
<em><u>There are two simple rules to remember: </u></em>
- When you multiply a negative number by a positive number then the product is always negative.
- When you multiply two negative numbers or two positive numbers then the product is always positive.
So the above expression becomes:
Removing the brackets we get,
Combining the like terms,
Thus the resulting polynomial is found