Answer:
c=2
Step-by-step explanation:
All polynomials are continuous and differentiable on the set of real numbers.
So we just need to confirm on the given interval that f(1)=f(3).
f(1)=1-12(1)+3(1)^2
f(1)=1-12+3
f(1)=-8
f(3)=1-12(3)+3(3)^2
f(3)=1-36+27
f(3)=-8
So this means there is c in (1,3) such that f'(c)=0.
To solve that equation we must differentiate.
f(x)=1-12x+3x^2
f'(x)=0-12+6x
f'(x)=-12+6x
Remember we need yo solve f'(c)=0 for c.
So we need to solve -12+6c=0.
-12+6c=0
Add 12 on both sides:
6c=12
Divide both sides by 6:
c=2
Answer: Part A 11520 for the blue one
Part B for the orange one is 12
Step-by-step explanation:
Multiply them all by each other
Answer:
Step-by-step explanation:
A solution is any value of a variable that makes the specified equation true. A solution set is the set of all variables that makes the equation true. The solution set of 2y + 6 = 14 is {4}, because 2(4) + 6 = 14.
The answer to this is A and D. A and D are both rational because they contain repeating numbers.
B) could've been the answer but it doesn't show any repeating numbers
C) Doesn't have a repeating number.
So A and D are the answers. (if there is only one option for this answer then D should be the answer)
Hoped this helped :)
Have a great day
