Answer:
Step-by-step explanation:
The standard equation of a hyperbola is given by:
where (h, k) is the center, the vertex is at (h ± a, k), the foci is at (h ± c, k) and c² = a² + b²
Since the hyperbola is centered at the origin, hence (h, k) = (0, 0)
The vertices is (h ± a, k) = (±√61, 0). Therefore a = √61
The foci is (h ± c, k) = (±√98, 0). Therefore c = √98
Hence:
c² = a² + b²
(√98)² = (√61)² + b²
98 = 61 + b²
b² = 37
b = √37
Hence the equation of the hyperbola is:
Answer:
segment IG ≅ segment LJ
Step-by-step explanation:
Please refer to the attached image as per the triangles as given in the question statement.
Given that:
and
<em>SAS congruence </em>between two triangles states that two triangles are congruent if two corresponding sides and the angle between the two sides are congruent.
We are given that one angle and one sides are congruent in the given triangles.
We need to prove that other sides that makes this angle are also congruent.
To show the triangles are congruent i.e. by SAS congruence we need to prove that
segment IG ≅ segment LJ
Let us use Distance formula to find IG and LJ:
Hence, segment IG ≅ segment LJ
ΔGHI ≅ ΔJKL by SAS
