All categories

3 years ago

Find the values of x and y.

Mathematics

1 answer:

babunello [35]3 years ago

8 0

Answer:

x=21°. :Angles subtended by the same arc

y=42°. :180-(117+21),angles subtended by the same arc

You might be interested in

1. If p(x) = 3x + 4x² - 5x +8, find p(-2).

levacccp [35]

Step-by-step explanation:

$\small{\underline{\tt{\red{Given}}}}$

$\rightarrow$ p(x) = -2

$\small{\underline{\tt{\green{solution}}}}$

$\rightarrow$ $p(x) = 3x + {4x }^{2} - 5x + 8$

$\rightarrow$ $p( - 2) = 3( - 2) + 4( { - 2}^{2} ) - 5( - 2) + 8$

$\rightarrow$ $p( - 2) = - 6 + 16 + 10 + 8$

$\rightarrow$ $p( - 2) = 10 + 18$

$\rightarrow$ $p( - 2) = 28$

$\small\boxed{p(-2) = 28 }$

Hope it helps

4 0

3 years ago

To start a road trip, a car encountered a traffic jam, traveling a total of m miles after the first hour and a total of m2 miles

Monica [59]

56 miles, The car traveled m miles during the first hour and m squared miles during the second hour. The ratio m/m squared = 1/7 and cross multiplying yields m squared = 7m, so m=7. This means that the total distance traveled was 7+7squared = 56 miles

5 0

3 years ago

Solve please help fast

Natalka [10]

Answer:

5. 40

7. 12

8. 52

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A recent survey of Arlington High School 11th grade students found that 56% were female and 58% like math as their favorite subj

7nadin3 [17]

<span>If 56% are female, and 58% have math as their favorite subject, then there are some female students who like math best, so they have been counted in both. We can added the given of 56% + 58% = 114%, then subtract the 76% who are either female or like math, to get 114% - 76% = 38% as the number of students who have been counted under both. This means that 38% are female students who like math as their favorite subject.
</span>

3 0

3 years ago

In a recent poll of 3011 adults, 73% said that they use the Internet. A newspaper claims that more than 75% of adults use the In

pishuonlain [190]

Answer:

$z=\frac{0.73 -0.75}{\sqrt{\frac{0.75(1-0.75)}{3011}}}=-2.534$

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

So then the correct option would be:

0.0057; reject the null hypothesis

Step-by-step explanation:

Data given and notation

n=3011 represent the random sample taken

$\hat p=0.73$ estimated proportion of adults who use internet

$p_o=0.75$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is more than 0.75:

Null hypothesis: $p\geq 0.75$

Alternative hypothesis: $p < 0.75$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.73 -0.75}{\sqrt{\frac{0.75(1-0.75)}{3011}}}=-2.534$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

So then the correct option would be:

0.0057; reject the null hypothesis

7 0

2 years ago