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Westkost [7]
3 years ago
8

Find the values of x and y.

Mathematics
1 answer:
babunello [35]3 years ago
8 0

Answer:

x=21°. :Angles subtended by the same arc

y=42°. :180-(117+21),angles subtended by the same arc

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Bill and Eugene left the airport at the same time. They traveled in opposite directions. Eugene traveled 21.1 km/h faster than B
gizmo_the_mogwai [7]

Answer:

56.3 kilometers per hour

Step-by-step explanation:

We know D = RT

where

D is distance

R is rate (speed)

T is time

Let's Bill's rate be "x". Thus using equation we can write:

D = xt

We know Eugene travelled 21.1 faster than Bill, so Eugene's rate is 21.1 + x. So we can write:

D = (21.1 + x)t

D = 21.1t + xt

Now, putting t = 1 in both since after 1 hour given, we have:

D = x(1)

D = x

and

D = 21.1(1) + x(1)

D = 21.1 + x

We know the sum of both the distance is 133.7, so we can write:

x + 21.1 + x = 133.7

Solving for x:

2x = 133.7 - 21.1

2x = 112.6

x = 112.6 / 2

x = 56.3 km/hr

This is Bill's rate: 56.3 kilometers per hour

8 0
3 years ago
Prove the following DeMorgan's laws: if LaTeX: XX, LaTeX: AA and LaTeX: BB are sets and LaTeX: \{A_i: i\in I\} {Ai:i∈I} is a fam
MariettaO [177]
  • X-(A\cup B)=(X-A)\cap(X-B)

I'll assume the usual definition of set difference, X-A=\{x\in X,x\not\in A\}.

Let x\in X-(A\cup B). Then x\in X and x\not\in(A\cup B). If x\not\in(A\cup B), then x\not\in A and x\not\in B. This means x\in X,x\not\in A and x\in X,x\not\in B, so it follows that x\in(X-A)\cap(X-B). Hence X-(A\cup B)\subset(X-A)\cap(X-B).

Now let x\in(X-A)\cap(X-B). Then x\in X-A and x\in X-B. By definition of set difference, x\in X,x\not\in A and x\in X,x\not\in B. Since x\not A,x\not\in B, we have x\not\in(A\cup B), and so x\in X-(A\cup B). Hence (X-A)\cap(X-B)\subset X-(A\cup B).

The two sets are subsets of one another, so they must be equal.

  • X-\left(\bigcup\limits_{i\in I}A_i\right)=\bigcap\limits_{i\in I}(X-A_i)

The proof of this is the same as above, you just have to indicate that membership, of lack thereof, holds for all indices i\in I.

Proof of one direction for example:

Let x\in X-\left(\bigcup\limits_{i\in I}A_i\right). Then x\in X and x\not\in\bigcup\limits_{i\in I}A_i, which in turn means x\not\in A_i for all i\in I. This means x\in X,x\not\in A_{i_1}, and x\in X,x\not\in A_{i_2}, and so on, where \{i_1,i_2,\ldots\}\subset I, for all i\in I. This means x\in X-A_{i_1}, and x\in X-A_{i_2}, and so on, so x\in\bigcap\limits_{i\in I}(X-A_i). Hence X-\left(\bigcup\limits_{i\in I}A_i\right)\subset\bigcap\limits_{i\in I}(X-A_i).

4 0
3 years ago
Austin is 69 years younger than Jamie. 3 years ago, Jamie's age was 4 times Austin's age. How old is Austin now?
matrenka [14]

Answer: 26 years old

Step-by-step explanation:

  1. Create an equation with Austin as x and Jamie as x+69 (I just like workin with addition signs more)= 4(x-3)= x+69-3
  2. Simplify the equations --> 4x-12=x+66
  3. Solve the equation: 3x-12=66 --> 3x=78 --> x=26

This is the same as other age problems, just with the extra step of distributing the multiplication.

4 0
3 years ago
Find the domain of the function f (x) = 2/x-4 + 1/x+2
Andreas93 [3]

As written, the denominator in both fractions is x, so the only restriction on the domain is ... x ≠ 0.

_____

We suspect you intend ...

... f(x) = 2/(x-4) +1/(x+2)

which is undefined when x = 4 or x = -2.

The domain is all real numbers except -2 and 4.

6 0
3 years ago
According to a bridal magazine, the average cost of a wedding reception for an American wedding is $8213. Assume that the averag
amm1812

Answer:

Point estimate of the corresponding population mean = $8,213

Step-by-step explanation:

Given:

Average cost of a wedding reception (x) = $8,213

Total number of sample (n) = 450

Standard deviation = $2185

Find:

Point estimate of the corresponding population mean

Computation:

Average cost of a wedding reception (x) = Point estimate of the corresponding population mean

Point estimate of the corresponding population mean = $8,213

7 0
3 years ago
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