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labwork [276]
2 years ago
12

HELLLLPPPP MEEEEEE!!!!!!

Mathematics
1 answer:
malfutka [58]2 years ago
8 0

Answer:

B I believe correct me if I'm wrong

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Dream borrowed $500 at an interest rate of 8%. At the end of the loan period, she had to pay back $530. How long was the loan fo
Aliun [14]

Answer:

The loan was for 9 months only

Step-by-step explanation:

In this question, we are concerned with calculating the time taken for a loan om an interest to be paid back

To calculate this, we use the simple interest formula

Mathematically;

I = PRT/100

where P is the principal which is the amount borrowed and that is $500 according to the question

R is the rate which is 8% according to the question

Interest can be calculated by subtracting the principal from the  amount paid back = 530-500 = 30$

We now plug these values into the equation

30 = (500 × 8× T)/100

100 × 30 = 4000T

T = 3000/4000

T = 0.75 (same as 0.75 × 12 months = 9 months)

5 0
3 years ago
Can someone plsss help me with this one problem plsss I’m trying to get a 90 and also can you explain how you got your answer
Karo-lina-s [1.5K]
From question,
lacy learned 34 recipes in 17 weeks,
so in 1 week she learns = 34/17 =2 recipes,
hence she learns 40 recipes in
= 40*2
=80 recipes.
7 0
3 years ago
Factor the expression 24x + 18y =
dangina [55]
24x = 2,2,2,3,x
18y = 2,3,3,y
3 0
3 years ago
Read 2 more answers
How many solutions are in 6x+30+4x=10(x+3)
Jobisdone [24]

First, let's simplify the equation.

6x + 30 + 4x = 10(x + 3)

  • Set up

10x + 30 = 10(x + 3)

  • Combine like terms

10x + 30 = 10x + 30

  • Apply the Distributive Property to the right hand side of the equation

30 = 30

  • Subtract 10x from both sides of the equation

Since the right and left sides of the equation are equal, we know that there must be an infinite number of solutions. This means that there is an infinite amount of values that we can substitute for x for the equation to be true.

8 0
3 years ago
Read 2 more answers
Integral of 1/ (a+b-(a-b)x*) dx <br> where (0
mylen [45]
\displaystyle\int\frac{\mathrm dx}{a+b-(a-b)x}=\frac1{b-a}\int\frac{\mathrm dy}y

where y=a+b-(a-b)x\implies \mathrm dy=(b-a)\,\mathrm dx. Then

\displaystyle\frac1{b-a}\int\frac{\mathrm dy}y=\frac{\ln|y|}{b-a}+C
\displaystyle\int\frac{\mathrm dx}{a+b-(a-b)x}=\frac{\ln|a+b-(a-b)x|}{b-a}+C
3 0
3 years ago
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