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2 years ago

A rectangular football field is 64 meters wide and 100 meters long. A player runs from one corner of the field in a

1 answer:

7 0

So this is going to create a right triangle which you and his run will create the hypotenuse, so we will use
a^2+b^2= c^2
a and b are given... 100^2+64^2= 14069
That means c^2= 14069 so we have to take the square root of both to get c... which gives us 118.7265766373 which to the nearest meter is 119.

You might be interested in

Find the value of x in the triangle shown below.

Crazy boy [7]

Answer:

i think its the same as one of the angles: 42º

correct me if im wrong

3 0

3 years ago

This morning, Kevin's car had 13.8 gallons of fuel. Now, 1.9 gallons are left. How much fuel did Kevin use?

lesantik [10]

Answer:

He used 11.9 gallons of fuel.

Step-by-step explanation:

You would subtract 1.9 from 13.8

Hope this helps!

7 0

2 years ago

Read 2 more answers

Solve this application problem using a system of equations: Dan and June mix two kinds of feed for pedigreed dogs. They wish to

wlad13 [49]

Answer:

50 pounds

Step-by-step explanation:

Dan and june mix two kind of feed for pedigreed dogs

Feed A worth is $0.26 per pound

Feed B worth is $0.40 per pound

Let x represent the cheaper amount of feed and y the costlier type of feed

x+y= 70..........equation 1

0.26x + 0.40y= 0.30×70

0.26x + 0.40y= 21.........equation 2

From equation 1

x + y= 70

x= 70-y

Substitutes 70-y for x in equation 2

0.26(70-y) + 0.40y= 21

18.2-0.26y+0.40y= 21

18.2+0.14y= 21

0.14y= 21-18.2

0.14y= 2.8

Divide both sides by the coefficient of y which is 0.14

0.14y/0.14= 2.8/0.14

y= 20

Substitute 20 for y in equation 1

x + y= 70

x + 20= 70

x= 70-20

x = 50

Hence Dan and june should use 50 pounds of the cheaper kind in the mix

4 0

3 years ago

Solve the system of linear equations. separate the x- and y- values with a coma.

kobusy [5.1K]

Solve the following system:
{7 x - 3 y = 37 | (equation 1)
{14 x + 11 y = 23 | (equation 2)
Swap equation 1 with equation 2:
{14 x + 11 y = 23 | (equation 1)
{7 x - 3 y = 37 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{14 x + 11 y = 23 | (equation 1)
{0 x - (17 y)/2 = 51/2 | (equation 2)

Multiply equation 2 by 2/17:
{14 x + 11 y = 23 | (equation 1)
{0 x - y = 3 | (equation 2)

Multiply equation 2 by -1:
{14 x + 11 y = 23 | (equation 1)
{0 x+y = -3 | (equation 2)
Subtract 11 × (equation 2) from equation 1:
{14 x+0 y = 56 | (equation 1)
{0 x+y = -3 | (equation 2)

Divide equation 1 by 14:
{x+0 y = 4 | (equation 1)
{0 x+y = -3 | (equation 2)
Collect results:
Answer: {x = 4
{y = -3

4 0

3 years ago

Graph a line with a slope of -5 that contains the point -3,-4

guapka [62]

Answer:

The equation of the line is 5x + y + 19 = 0

Step-by-step explanation:

The equation of the line with slope 'm' and given a point (x₁, y₁) passing through it we use the Slope - one - point form which is given by:

y - y₁ = m(x - x₁)

The point given is: (-3, -4) and the slope is -5.

We get the equation of the line to be:

y - (-4) = -5(x - (-3))

⇒ y + 4 = -5(x + 3)

⇒ y + 4 = -5x - 15

⇒ 5x + y + 19 = 0. is the required equation of the line.

4 0

3 years ago