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ivolga24 [154]
3 years ago
5

Solve this application problem using a system of equations: Dan and June mix two kinds of feed for pedigreed dogs. They wish to

make 70 pounds of feed worth $0.30 per pound by mixing Feed A worth $0.26 per pound with Feed B worth $0.40 per pound. How many pounds of the cheaper kind should they use in the mix
Mathematics
1 answer:
wlad13 [49]3 years ago
4 0

Answer:

50 pounds

Step-by-step explanation:

Dan and june mix two kind of feed for pedigreed dogs

Feed A worth is $0.26 per pound

Feed B worth is $0.40 per pound

Let x represent the cheaper amount of feed and y the costlier type of feed

x+y= 70..........equation 1

0.26x + 0.40y= 0.30×70

0.26x + 0.40y= 21.........equation 2

From equation 1

x + y= 70

x= 70-y

Substitutes 70-y for x in equation 2

0.26(70-y) + 0.40y= 21

18.2-0.26y+0.40y= 21

18.2+0.14y= 21

0.14y= 21-18.2

0.14y= 2.8

Divide both sides by the coefficient of y which is 0.14

0.14y/0.14= 2.8/0.14

y= 20

Substitute 20 for y in equation 1

x + y= 70

x + 20= 70

x= 70-20

x = 50

Hence Dan and june should use 50 pounds of the cheaper kind in the mix

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Step-by-step explanation:

In the unit circle, Ф is the angle between the terminal side and the positive part of the x-xis

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  • The terminal point on the positive part of the y-axis is (0, 1),which means Ф = 90° and cosФ = 0, sinФ = 1
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In a unit circle

∵ Ф = 270°

→ By using the 4th rule above

∴ The terminal point is (0, -1)

∴ sinФ = -1

∴ Terminal point (0, -1); sin Ø = -1

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Step-by-step explanation:

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The scores on the GMAT entrance exam at an MBA program in the Central Valley of California are normally distributed with a mean
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Answer:

58.32% probability that a randomly selected application will report a GMAT score of less than 600

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 591, \sigma = 42

What is the probability that a randomly selected application will report a GMAT score of less than 600?

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{600 - 591}{42}

Z = 0.21

Z = 0.21 has a pvalue of 0.5832

58.32% probability that a randomly selected application will report a GMAT score of less than 600

What is the probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{50}} = 5.94

This is the pvalue of Z when X = 600. So

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{5.94}

Z = 1.515

Z = 1.515 has a pvalue of 0.9351

93.51%  probability that a sample of 50 randomly selected applications will report an average GMAT score of less than 600

What is the probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600?

Now we have n = 50, s = \frac{42}{\sqrt{100}} = 4.2

Z = \frac{X - \mu}{s}

Z = \frac{600 - 591}{4.2}

Z = 2.14

Z = 2.14 has a pvalue of 0.9838

98.38% probability that a sample of 100 randomly selected applications will report an average GMAT score of less than 600

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