Ask question

Ask question

All categories

3 years ago

5

Solve this application problem using a system of equations: Dan and June mix two kinds of feed for pedigreed dogs. They wish to

make 70 pounds of feed worth $0.30 per pound by mixing Feed A worth $0.26 per pound with Feed B worth $0.40 per pound. How many pounds of the cheaper kind should they use in the mix

1 answer:

wlad13 [49]3 years ago

4 0

Answer:

50 pounds

Step-by-step explanation:

Dan and june mix two kind of feed for pedigreed dogs

Feed A worth is $0.26 per pound

Feed B worth is $0.40 per pound

Let x represent the cheaper amount of feed and y the costlier type of feed

x+y= 70..........equation 1

0.26x + 0.40y= 0.30×70

0.26x + 0.40y= 21.........equation 2

From equation 1

x + y= 70

x= 70-y

Substitutes 70-y for x in equation 2

0.26(70-y) + 0.40y= 21

18.2-0.26y+0.40y= 21

18.2+0.14y= 21

0.14y= 21-18.2

0.14y= 2.8

Divide both sides by the coefficient of y which is 0.14

0.14y/0.14= 2.8/0.14

y= 20

Substitute 20 for y in equation 1

x + y= 70

x + 20= 70

x= 70-20

x = 50

Hence Dan and june should use 50 pounds of the cheaper kind in the mix

You might be interested in

When 7 is subtracted from two third of the square of a number it becomes 17 find the number

Dmitry [639]

Answer: 6 or -6

hello,

Step-by-step explanation:

Let say n the number

$\dfrac{2}{3} *n^2-7=17\\\Longrightarrow\ \dfrac{2}{3} *n^2=24\\\Longrightarrow\ n^2=\dfrac{3*24}{2}\\\Longrightarrow\ n^2=36\\\Longrightarrow\ (n-6)(n+6)=0\\\\n=6\ or\ n=-6\\$

8 0

2 years ago

A pet store sells goldfish and hermit crabs,

Elis [28]

Answer:

$Cost = \$28$

Step-by-step explanation:

Given

Represent Goldfish with g and hermit crabs with h.

The first statement, we have:

$7g + 3h = 26$

The second statement, we have:

$4g + 5h = 28$

Required

Determine the selling price of 6 goldfish and 4 hermit crabs

The equations are:

$7g + 3h = 26$ --- (1)

$4g + 5h = 28$ --- (2)

Make g the subject in (2)

$4g + 5h = 28$

$4g = 28 - 5h$

Divide both sides by 4

$g = \frac{1}{4}(28 - 5h)$

Substitute $\frac{1}{4}(28 - 5h)$ for g in (1)

$7g + 3h = 26$

$7(\frac{1}{4}(28 - 5h)) + 3h = 26$

$\frac{7}{4}(28 - 5h) + 3h = 26$

Multiply through by 4

$4 * \frac{7}{4}(28 - 5h) + 4*3h = 26*4$

$7(28 - 5h) + 4*3h = 26*4$

Open bracket

$196 - 35h + 12h = 104$

$196 -23h = 104$

Collect Like Terms

$-23h = 104-196$

$-23h = -92$

Make h the subject

$h = \frac{-92}{-23}$

$h = \frac{92}{23}$

$h = 4$

Substitute 4 for h in $g = \frac{1}{4}(28 - 5h)$

$g = \frac{1}{4}(28 - 5*4)$

$g = \frac{1}{4}(28 - 20)$

$g = \frac{1}{4}(8)$

$g = 2$

This implies that:

1 goldfish = $2

1 hermit crab = $4

The cost of 6 goldfish and 4 hermit crabs is:

$Cost = 6g + 4h$

$Cost = 6*\$2 + 4*\$4$

$Cost = \$12 + \$16$

$Cost = \$28$

5 0

3 years ago

Mustafa contributes 11% of his $67,200 annual salary to his 401(k) plan. What is his pretax income?

Juli2301 [7.4K]

11% of $67,200.
We need to keep in mind that some words and numbers here aren't important, like 401(k) plan.
So what is 11% of $67,200?

$\frac{11}{100} * $67,200
$

$11*$672$

$7392

Hope this helps!

5 0

3 years ago

Read 2 more answers

Are these parallel, perpendicular, or neither?

Elina [12.6K]

Answer: I think it’s neither

Explanation:

The line is parallel unless the slope is the same and with a different y-intercept

The line are perpendicular unless the one of the slope is the negative reciprocal of the other.

And both equation didn’t meet any of the requirement.

5 0

2 years ago

When his elevation is higher than 1600

luda_lava [24]

His elevation is higher than 1600, where there is less oxygen and, air which technically contains oxygen, and the fact that elevation means going “up”.

6 0

3 years ago