The weights (to the nearest pound) of some boxes to be shipped are found to be:. Weight 65 68 69 70 71 72 90 95 frequency 1 2 5 8 7 3 2 2 Their mean weight is 72.97 pounds. What is the standard deviation of these weights? The standard deviation, to the nearest tenth, is a0.
1 answer:
A is the weight B is the frequency C is weight times frequency D is mean minus weight E is D raised to the 2nd power ; variance F is E times frequency ; total variance A B C D E F 65 1 65 7.97 63.47 63.47 68 2 136 4.97 24.70 49.40 69 5 345 3.97 15.76 78.80 70 8 560 2.97 8.82 70.57 71 7 497 1.97 3.88 27.17 72 3 216 0.97 0.94 2.82 90 2 180 17.03 290.02 580.04 95 <u> 2 </u> <u> 190 </u> 22.03 485.32 <u> 970.64</u> 30 2,189 1,842.91 2,189 / 30 = 72.97 mean 1,842.91 / 30 = 61.43 variance √61.43 = 7.8377 or 7.84 standard deviation.
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